is the algebraic representation for an exponential function
Step-by-step explanation:
Given:
f(x + 1) = 4.f(x)
f(3) = 16
To Find:
Algebraic representation for an exponential function=?
Solution:
From the formula f(x+n) = f(x)
when n= 1, x= 3
f(3+1)= 4(1)f(3)
f(4)= 4f(3)
Substituting the value of f(3)
f(4)= 4f(3)
f(4)= 4 x 16
f(4)= 64
f(4)=
f (5) = x 16
f (5) = x
f(5)=
Similarly,
F(6) =
Hence,
To evaluate a function at a given input, you have to substitute every occurrence of the variable with that particular value.
So, for the first function, you have
The name of the variable is obviously irrelelvant, so the same goes for the second function:
Answer:
To prove that 3·4ⁿ + 51 is divisible by 3 and 9, we have;
3·4ⁿ is divisible by 3 and 51 is divisible by 3
Where we have;
= 3·4ⁿ + 51
= 3·4ⁿ⁺¹ + 51
-
= 3·4ⁿ⁺¹ + 51 - (3·4ⁿ + 51) = 3·4ⁿ⁺¹ - 3·4ⁿ
-
= 3( 4ⁿ⁺¹ - 4ⁿ) = 3×4ⁿ×(4 - 1) = 9×4ⁿ
∴ -
is divisible by 9
Given that we have for S₀ = 3×4⁰ + 51 = 63 = 9×7
∴ S₀ is divisible by 9
Since -
is divisible by 9, we have;
-
=
-
is divisible by 9
Therefore is divisible by 9 and
is divisible by 9 for all positive integers n
Step-by-step explanation:
