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Svet_ta [14]
2 years ago
6

What is the mass of 0.5 moles of NaCl

Chemistry
2 answers:
jeka57 [31]2 years ago
8 0

Answer:

29.25 g

Explanation:

mole =  \dfrac{mass}{molar \: mass}

mass = 0.5 × 58.5 [ 23 + 35.5]

= 29.25 gm

Debora [2.8K]2 years ago
6 0

Answer:

29.25g

Explanation:

m=0.5×(23+35.5)

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2 years ago
write the equilibrium expression for the base ionization of the weak base of methylamine, ch3 nh2 . hint: first write the balanc
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4 0
1 year ago
How many moles in 4.65 g of Helium?
Maru [420]

Answer:

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Explanation:

7 0
3 years ago
Yet a third pair of compounds of manganese and oxygen is 50.48% and 36.81% oxygen respectively. In what small whole number ratio
Mariulka [41]

Answer:

The number ratio is 4:7

Explanation:

Step 1: Data given

Compound 1 has 50.48 % oxygen

Compound 2 has 36.81 % oxygen

Molar mass oxygen = 16 g/mol

Molar mass manganese = 54.94 g/mol

Step 2: Calculate % manganes

Compound 1: 100 - 50.48 = 49.52 %

Compound 2: 100 - 36.81 = 63.19 %

Step 3: Calculate mass

Suppose mass of compounds = 100 grams

Compound 1:

 50.48 % O = 50.48 grams

 49.52 % Mn = 49.52 grams

Compound 2:

36.81 % O = 36.81 grams

63.19 % Mn = 63.19 grams

Step 4: Calculate moles

Compound 1

Moles O = 50.48 grams / 16.0 g/mol = 3.155 moles

Moles Mn = 49.52 grams / 54.94 g/mol = 0.9013 moles

Compound 2

Moles O = 36.81 grams / 16.0 g/mol = 2.301 moles

Moles Mn = 63.19 grams / 54.94 g/mol = 1.150 moles

Step 5: calculate mol ratio

We will divide by the smallest amount of moles

Compound 1

O: 3.155/0.9013 = 3.5

Mn: 0.9013 / 0.9013 = 1

Mn2O7

Compound 2

O: 2.301 / 1.150 = 2

Mn: 1.150 / 1.150 = 1

MnO2

The number ratio is 2:3.5 or 4:7

7 0
3 years ago
Give the numbers of significant figures indicated 60.1<br><br> 0 <br> 3 <br> 1 <br> 2
denpristay [2]
3 significant figures
4 0
3 years ago
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