Question

How many moles of KCIO3 are required to produce 58.3 grams of 02? 2 KCIO3 —> 2 KCI + 3 O2

Answer 1

Answer:

1.21 mol KClO₃

General Formulas and Concepts:

Atomic Structure

• Reading a Periodic Table
• Moles
• Mole Ratio

Stoichiometry

• Analyzing reactions rxn
• Using Dimensional Analysis

Explanation:

Step 1: Define

Identify variables

[rxn] 2KClO₃ → 2KCl + 3O₂

[Given] 58.3 g O₂

[Solve] mol KClO₃

Step 2: Identify Conversions

[rxn] 2 mol KClO₃ → 3 mol O₂

[PT] Molar Mass of O: 16.00 g/mol

Molar Mass of O₂: 2(16.00) = 32.00 g/mol

Step 3: Convert

1. [DA] Set up:                                                                                                       $\displaystyle 58.3 \ g \ O_2(\frac{1 \ mol \ O_2}{32.00 \ g \ O_2})(\frac{2 \ mol \ KClO_3}{3 \ mol \ O_2})$
2. [DA] Divide/Multiply [Cancel out units]:                                                           $\displaystyle 1.21458 \ mol \ KClO_3$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

1.21458 mol KClO₃ ≈ 1.21 mol KClO₃