The volume of copper : 3.24 ml
<h3>Further explanation
</h3>
Density is a quantity derived from the mass and volume
Density is the ratio of mass per unit volume
With the same mass, the volume of objects that have a high density will be smaller than objects with a smaller type of mass
The unit of density can be expressed in g/cm³ or kg/m³
Density formula:
ρ = density
, g/cm³ or kg/m³
m = mass
, g or kg
v = volume
, cm³ or m³
A common example is the water density of 1 gr / cm³
The density of copper : 8.96 gr/ml
mass of copper : 29 g
then the volume :
The question is incomplete, complete question is :
In an organic structure, you can classify each of the carbons as follows: Primary carbon (1°) = carbon bonded to just 1 other carbon group Secondary carbon (2°) = carbon bonded to 2 other carbon groups Tertiary carbon (3°) = carbon bonded to 3 other carbon groups Quaternary carbon (4°) = carbon bonded to 4 other carbon groups How many carbons of each classification are in the structure below? How many total carbons are in the structure? How many primary carbons are in the structure? How many secondary carbons are in the structure? How many tertiary carbons are in the structure? How many quaternary carbons are in the structure?
Structure is given in an image?
Answer:
There are 10 carbon atoms in the given structures out of which 6 are 1° , 1 is 2° , 2 are 3° and 1 is 4°.
Explanation:
Total numbers of carbon = 10
Number of primary carbons that is carbon joined to just single carbon atom = 6
Number of secondary carbons that is carbon joined to two carbon atoms = 1
Number of tertiary carbons that is carbon joined to three carbon atoms = 2
Number of quartenary carbons that is carbon joined to four carbon atoms = 1
So, there are 10 carbon atoms in the given structures out of which 6 are 1° , 1 is 2° , 2 are 3° and 1 is 4°.
Window cleaner is ammonia dissolved in water. This is an example of a _______.
Answer:
Reaction is non-spontaneous when T > 738.5K and spontaneous when T < 738.5K
Explanation:
A reaction is non-spontaneous when ΔG° > 0 and is spontaneous when ΔG° < 0
ΔG° is defined as:
ΔG° = ΔH° - TΔS°
ΔG° will be > 0 (non-spontaneous) when ΔH° > TΔS° and vice versa. Thus:
-16100J > T × -21.8J/K
738.5K > T
That means the reaction is <em>non-spontaneous when T > 738.5K and spontaneous when T < 738.5K</em>
I hope it helps!
