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3 years ago

Which electrophiles can react with an enol?

1 answer:

8 0

THE MOLECULE HAS A C=C AND AN -OH GROUP, SO IT IS CALLED AN ENE/OL, I.E., AN ENOL. ENOLS CAN BE FORMED ONLY FROM CARBONYL COMPOUNDS WHICH HAVE ALPHA HYDROGENS. THEY CAN BE FORMED BY ACID OR BASE CATALYSIS, AND ONCE FORMED ARE HIGHLY REACTIVE TOWARD ELECTROPHILES, LIKE BROMINE.

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Directions: Match the terms in Column Il with the definitions in Column / Write the letter of the correct term in

kobusy [5.1K]

<h2>What is cell, tissue, organ and organ system?</h2>

Organ system----- when different organs combine together forming organ system.
Cell---- is the smallest living unit in the body that performs body function.
Organ--- two or more different types of tissues working together forming organs.
Tissues--- groups of similar cells doing the same work is known as tissue.
Nerve cell---- a long-branched type of cell that sends messages quickly from sensory cells to nervous system.
Bone cell----- A type of cell surrounded by calcium and phosphorous.
Specialized job ---- Each type of cell has a specific job to do.

Learn more about cell here: brainly.com/question/13123319

Learn more: brainly.com/question/26095786

3 0

2 years ago

Which field of science studies the composition and matter

Aleks04 [339]

I think chemistry field of science

8 0

3 years ago

The reaction between nitrogen dioxide and carbon monoxide is NO2(g)+CO(g)→NO(g)+CO2(g)NO2(g)+CO(g)→NO(g)+CO2(g) The rate constan

galina1969 [7]

Answer:

$k_2=2.55\ {Ms}^{-1}$

Explanation:

Using the expression,

$\ln \dfrac{k_{1}}{k_{2}} =-\dfrac{E_{a}}{R} \left (\dfrac{1}{T_1}-\dfrac{1}{T_2} \right )$

Where,

$k_1\ is\ the\ rate\ constant\ at\ T_1$

$k_2\ is\ the\ rate\ constant\ at\ T_2$

$E_a$ is the activation energy

R is Gas constant having value = 8.314 J / K mol

$k_2=?$

$k_1=2.57\ {Ms}^{-1}$

$T_1=701\ K$

$T_2=525\ K$

$E_a=1.5\times 10^2\ kJ/mol$

So,

$\ln \:\frac{2.57}{k_2}\:=-\frac{1.5\times \:10^2}{8.314}\times \left(\frac{1}{701}-\frac{1}{525}\right)\:\:$

$k_2=\frac{2.57}{e^{\frac{352}{40796.798}}}=2.55\ {Ms}^{-1}$

7 0

3 years ago

In an experiment, Lydia added 50 grams of sugar to 200 milliliters of water. She stirred the mixture, and the sugar eventually d

grandymaker [24]

Answer:

A. A physical change took place during this experiment

Explanation:

A physical change is one of the changes that occurs in a reaction. It is a kind of change characterized by no change to the chemical composition of the substances involved. It involves reactions such as melting, change of state, freezing, boiling etc.

According to this question, Lydia added 50 grams of sugar to 200 milliliters of water, then, stirred the mixture, until the sugar eventually dissolved into the water and couldn’t be seen. This change involved no change in color, odor, or temperature. Hence, Lydia's experiment represents a PHYSICAL CHANGE because only DISSOLUTION occured.

In an experiment, Lydia added 50 grams of sugar to 200 milliliters of water. She stirred the mixture, and the sugar eventually dissolved into the water and couldn’t be seen. The volume of the solution increased, but there was no noticeable change in color, odor, or temperature. Which statement best describes what happened in Lydia’s experiment? A. A physical change took place during this experiment. B. A chemical change took place during this experiment. C. A compound was formed during this experiment. D. A heterogeneous mixture was

3 0

3 years ago

(True or False)<br> A single particle has NO temperature.<br> True<br> False

Elenna [48]

Answer:

True

Explanation:

No, a single particle cannot have a temperature at all, because temperature is a property of a large number of particles.- this is not my own words the website I got it from is https://www.quora.com/Can-a-single-particle-have-any-temperature

6 0

2 years ago