When equal volumes of ethanol and water are mixed to form a solution, the entropy of the resulting solution increases. This is because ethanol and water are both polar substances, making them miscible. The solubility of both substances is high because they have similar attractions due to the presence of hydrogen bonding. This means that molecules of water and ethanol freely move with each other, therefore increasing the dispersal, randomness, and disorder (entropy) of the system.
Answer:
True
Explanation:
*For polar and associated substances, methods based on four should be used four or more parameters, like analytical equation of state
*The term "analytical equation of state" implies that the function
It contains powers of v not greater than four.
*Most expressions are of the cubic type and are grouped into
the so-called cubic equations of state.
*Cubic EoS calls are very popular in simulation of
processes due to its robustness and its simple extension to mixtures.
*They are based on the van der Waals state equation of more than
100 years.
A neutralization reaction is when an acid and a base react to form water and a salt and involves the combination of H+ ions and OH- ions to generate water. The neutralization of a strong acid and strong base has a pH equal to 7.
Answer:
4:5
Explanation:
Let x represent the fraction of the mix that is hot water. Then the temperature of the mix is ...
60x +15(1-x) = 40·1
45x = 25 . . . . . . . . . subtract 15
x = 25/45 = 5/9 . . . divide by the coefficient of x
This is the fraction that is hot water, so the fraction that is cold water is ...
1-5/9 = 4/9
The ratio of cold to hot is ...
cold : hot = (4/9) : (5/9) = 4 : 5
_____
<em>Additional comments</em>
The problem assumes that the energy contained in a given mass of water is proportional to its temperature. That is almost true, sufficiently so that we can reasonably use that approximation.
If heat loss is figured into the problem, then additional information is needed regarding the energy content of water at temperatures in the range of interest. That is not provided by this problem statement, so we have ignored the heat loss.
