Answer:
The average of given values is 2.1221 ml
Explanation:
Given data:
Given measurements = 3.00 ml , 2.0 ml, 2.987 × 10⁻³ml , 3.4856 ml
Average value of given measurements = ?
Solution:
Formula:
Average value = sum of all measurement / total number of measurements
2.987 × 10⁻³ml = 0.002987 ml
Now we will put the values.
Average value = 3.00 ml + 2.0 ml + 0.002987 ml+ 3.4856 ml / 4
Average value = 8.488587 ml / 4
Average value = 2.1221 ml
The average of given values is 2.1221 ml
My Friday is going good and I might get to go over to my BFF house!!!
Answer:
A)The characteristic frequency to look out for is 1720-1740 cm-1 (for C=O) for which will disappear in the end product but initially present in the reactant.
B)Characteristic frequency present in the infrared spectrum will be at a peak of 3300-3400 cm-1 which will be due to O-H stretch.
C)If the product is wet with water there will be no change in the infrared spectrum
Explanation:
The characteristic frequency to look out for is 1720-1740 cm-1 (for C=O) for which will disappear in the end product but initially present in the reactant.
Characteristic frequency present in the infrared spectrum will be at a peak of 3300-3400 cm-1 which will be due to O-H stretch.
If the product is wet with water there will be no change in the infrared spectrum
Answer:
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Explanation:
Answer: [Ne] 3s¹ sodium electron configuration
