Question

How many particles are present in 15.0 g of CCL4? (Show work please:))

Answer 1

Answer:

5.86*10^22particles

Explanation:

First obtain the molar mass of tetrachloromethane then compare the given mass in the question with Avogadro's number as shown in the solution. Note that the Avogadro's number is the number of particles contained by one mole of all substances at standard temperature and pressure. According to Avogadro, at the same temperature and pressure, one mole of all substances contain equal number of molecules

Answer 2

1) Calculate the molar weight. 12.000 + 4*(35.45)
2) Divide 15.0 by the molar weight to get moles
3) Multiply by Avogado's number of get the number of molecules.