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3 years ago

How many particles are present in 15.0 g of CCL4? (Show work please:))

Chemistry

2 answers:

Fed [463]3 years ago

7 0

Answer:

5.86*10^22particles

Explanation:

First obtain the molar mass of tetrachloromethane then compare the given mass in the question with Avogadro's number as shown in the solution. Note that the Avogadro's number is the number of particles contained by one mole of all substances at standard temperature and pressure. According to Avogadro, at the same temperature and pressure, one mole of all substances contain equal number of molecules

SCORPION-xisa [38]3 years ago

6 0

1) Calculate the molar weight. 12.000 + 4*(35.45)
2) Divide 15.0 by the molar weight to get moles
3) Multiply by Avogado's number of get the number of molecules.

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In the image to the right, a student is completing an experiment. What should the student do in order to follow the safety guide

attashe74 [19]

Wear gloves when handling chemicals.

Make sure that none of the liquids near the Bunsen burner are flammable.

Explanation:

The safety precautions the student must apply while completing his experiment is that he/she must wear gloves while handling the chemicals and they must make sure that none of the liquids near the Bunsen burner are flammable.

Safety guidelines provides a detailed and careful way to carry out experiment and observations in the laboratory.
This is all in a bid to accidents in the workspace.
It is a good practices to wear gloves and laboratory coat while handling chemicals.
Also make sure to put out the Bunsen burner when not in use.
Keep papers and books away from the work area. Chemicals and papers are not friends.
Ensure that flammable liquids are not close to the Burner.

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3 years ago

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Suppose a 1.0 ml air bubble is trapped in the top of your buret and you do not notice it before measuring our liquid samples wit

Nadusha1986 [10]

The percentage error that would be introduced in a 35.0 mL sample of liquid is 2.86%

<h3>Data obatined from the question</h3>

From the question given, the following data were obtained:

Absolute error = 1 mL
True measurement = 35 mL
Perecentage error =?

<h3>How to determine the percentage error</h3>

The percentage error that would be introduced can be obtained as illustrated below:

Percentage error = (Absolute error / True measurement) × 100

Percentage error = (1 / 35) × 100

Percentage error = 2.86%

Thus, percentage error that would be introduced is 2.86%

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1 year ago

Pls help which law is that???

MAXImum [283]

Answer:

it is newtons third law

Explanation:

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3 years ago

Read 2 more answers

In order for a roller coaster to work, why does the hill the cart climbs need to be higher than the top of the loop?

m_a_m_a [10]

Answer:

Explanation:

At the highest point of the first and tallest slope, your potential energy is at its most elevated it will at any point be on this ride. As you plunge, your potential energy diminishes until it's totally gone at the lower part of the slope." The more limited the slope the exciting ride climbs, the more prominent its active energy.

Another way of saying is that

A roller ride works utilizing gravity. the underlying slope must be sufficiently high that gravity can create sufficient force to finish the course.

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6 0

2 years ago

suppose 100ml of perchloric acid is neutralized by exacly 46.9 ml of 0.75m lithium hydroxide.what is the concentration of the pe

allochka39001 [22]

Answer:

0.352M

Explanation:

First, we need to write a balanced equation for the reaction between perchloric acid and lithium hydroxide. This is shown below:

HClO4 + LiOH —> LiClO4 + H2O

From the balanced equation above, we obtained:

nA (mole of the acid) = 1

nB (mole of the base) = 1

Data obtained from the question include:

Va (volume of the acid) = 100mL

Ca (concentration of the acid) =?

Vb (volume of the base) = 46.9 mL

Cb (concentration of the base) = 0.75M

Using CaVa/CbVb = nA/nB, the concentration of the acid can obtained as follow:

CaVa/CbVb = nA/nB

Ca x 100 / 0.75 x 46.9 = 1

Cross multiply to express in linear form

Ca x 100 = 0.75 x 46.9

Divide both side by 100

Ca = (0.75 x 46.9) /100

Ca = 0.352M

Therefore the concentration of the acid is 0.352M

6 0

3 years ago