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maksim [4K]
3 years ago
11

Jessie sorted the coins in her bank. She made 7 stacks of 6 dimes and 8 stacks of 5 nickels. She then found 1 dime and 1 nickel.

How many dimes and nickels does Jessie have in all?
Mathematics
1 answer:
ANEK [815]3 years ago
4 0
Hello!

So, Jessie made 7 stacks of dimes and 8 stacks of nickels.

Each stack of dimes has 6 dimes.

Each stack of nickels has 5 nickels. Multiply:

6 × 7 = 42

8 × 5 = 40

Then she finds another dime and another nickel.

42 + 1 = 43

40 + 1 = 41

43 + 41 = 84

ANSWER:

Jessie has 43 dimes, 41 nickels, and 84 coins in all.
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Answer: X = y - yi - 7i

               Y = (x + 7i)/(1 - i)

Step-by-step explanation: for the case of (X) you only need to pass the 7i to the other side with the subtraction sign (-7i), then we get this equation:

x + 7i = y − yi

X = y - yi - 7i

in the case of the (Y), first we select the common multiple.

y - yi = y(1 - i)

if we replace it in the original expression, we get the following equation:

x + 7i = y(1 - i)

after that you can pass the value (1 - i) to the other side dividing,

Y = (x + 7i)/(1 - i)

6 0
3 years ago
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lozanna [386]
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3 years ago
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Mazyrski [523]

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3 years ago
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qaws [65]
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rusak2 [61]

Answer:

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Step-by-step explanation:

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