Answer:
think the first one is Na small 2 CL small 3
second one is NaHCO small 4
Answer:
im no expert i believe 42
hope it helps
Explanation:
Answer:
17.1 L
Explanation:
P1V1/T1 = P2V2/T2 T is in K
P1V1/T1 * T2/P2 = V2
735 * 7.31 / (45+273.15) * (55+ 273.15)/325 = V2
V2 = 17.1 L
Answer:
c = 4016.64 j/g.°C
Explanation:
Given data:
Mass of substance = 2.50 g
Calories release = 12 cal (12 ×4184 = 50208 j)
Initial temperature = 25°C
Final temperature = 20°C
Specific heat of substance = ?
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Solution:
Q = m.c. ΔT
ΔT = T2 - T1
ΔT = 20°C - 25°C
ΔT = -5°C
50208 j = 2.50 g . c. -5°C
50208 j = -12.5 g.°C .c
50208 j /-12.5 g.°C = c
c = 4016.64 j/g.°C
