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Scorpion4ik [409]
3 years ago
10

How many different compounds are possible, changing only the cis/trans arrangements around these two double bonds?

Chemistry
1 answer:
insens350 [35]3 years ago
3 0
Check the attached file for the answer.

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The difference between diffusion and osmosis is that osmosis deals only with ________.
Nat2105 [25]
Osmosis deals only with D. Water. Diffusion and Osmosis are relatively the same thing besides the fact that water is largely incorporated with the osmosis.
6 0
3 years ago
What is the molar solubility of MgF2 in a 0.36 M Mg(NO3)2 solution? For MgF2, Ksp = 8.4 × 10^–8
Valentin [98]

Answer:

2.4 × 10⁻⁴ M

Explanation:

Step 1: Calculate the concentration of Mg²⁺ coming from Mg(NO₃)₂

Mg(NO₃)₂ is a strong electrolyte and the molar ratio of Mg(NO₃)₂ to Mg²⁺ is 1:1. The initial molar concentration of Mg²⁺ is 1/1 × 0.36 M = 0.36 M.

Step 2: Make an ICE chart for the solution of MgF₂

        MgF₂(s) ⇄ Mg²⁺(aq) + 2 F⁻(aq)

I                           0.36             0

C                           +S             +2S

E                         0.36+S         2S

The solubility product constant is:

Ksp = [Mg²⁺] × [F⁻]² = (0.36+S) × (2S)²

Since S <<< 0.36, 0.36+S ≈ 0.36.

Ksp = 0.36 × 4S² = 8.4 × 10⁻⁸

S = 2.4 × 10⁻⁴ M

7 0
3 years ago
At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. What partial pressur
fenix001 [56]

At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. 4.25 atm is the  partial pressure of He would give a solubility of 0.200 M.

<h3>What is Henry's Law ?</h3>

Henry's Law is a gas law states that at a constant temperature the amount of gas that dissolved in a liquid is directly proportional to the partial pressure of that gas.

<h3>What is relationship between Henry's Law constant and Solubility ?</h3>

The solubility of gas is directly proportional to partial pressure.

It is expressed as:

S_{\text{gas}} = K_{H} P_{\text{gas}}

where,

S_{\text{gas}} = Solubility of gas

K_{H} = Henry's Law constant

P_{\text{gas}} = Partial pressure of gas

Now put the values in above expression we get

S_{\text{gas}} = K_{H} P_{\text{gas}}

0.080M = K_{H} × 1.7 atm

K_{H} = \frac{0.080\ M}{1.7\ \text{atm}}

      = 0.047 M/atm

Now we have to find the partial pressure of He

S_{\text{gas}} = K_{H} P_{\text{gas}}

0.200 M = 0.047 M/atm × P_{\text{gas}}

P_{\text{gas}} = \frac{0.200 M}{0.047\ \text{M/atm}}

       = 4.25 atm

Thus from the above conclusion we can say that At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. 4.25 atm is the  partial pressure of He would give a solubility of 0.200 M.

Learn more about the Henry's Law here: brainly.com/question/23204201

#SPJ4

3 0
1 year ago
A sample of a substance has a mass of 4.2 grams and a volume of 6 milliliters
allsm [11]

Answer:

Density of the substance is 0.7

Explanation:

4.2/6 = 0.7

6 0
3 years ago
Read 2 more answers
Two masses exerting a force on each other is an example of What????
trasher [3.6K]

Newtons universal law of gravitation

hope this helps

8 0
3 years ago
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