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eimsori [14]
1 year ago
14

What is the area of a square with sides of length 2 1/2 cm?

Mathematics
1 answer:
Oduvanchick [21]1 year ago
6 0

The area of the square with the sides 2 1/2 cm will be A=6.25 square cm.

<h3>What is the area?</h3>

The space covered by the square in the two-dimensional plane will be the area of the square. Square actually covers the area with four equal sides.

The formula for the area of the square will be given as:-

A=Side x Side

A= 2 1/2 x2 1/2

A=5/2x5/2

A=2.5x2.5

A= 6.25 square cm

To know more about the area follow

brainly.com/question/3948796

#SPJ1

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Answer:

The narrative in the question can not be described as a function

Step-by-step explanation:

For the purpose of clarity, we will rephrase the question. The key point in the question  is to determine if the price and the model are related and if they fit into independent and dependent function.

Moving forward, to properly answer this question, it will be good for us to understand what dependent and independent functions are.

DEPENDENT FUNCTIONS: These are functions or can also be refereed to as variable that represents quantities or values whose parameter depends on how the independent variable is manipulated.

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You are doing job to earn your a salary. For each project you do, you earn $10 dollar. In this case, the dependent variable is the amount of money you earn because the amount of money you earn depends on how many job or project you do.

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Going back to the narrative of the question, the narrative in the question can not be described as a function because the two identifies variables which are the price and the model years are been altered due to the fact that it is a used car lot so they have both lost their true value or worth. However, some might argue that price here is the independent function or variable while model year is the dependent variable.

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Recall the binomial theorem.

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\left(1 + \dfrac x3\right)^7 = \displaystyle\sum_{k=0}^7 \binom 7k 1^{7-k} \left(\frac x3\right)^k = \sum_{k=0}^7 \binom 7k \frac{x^k}{3^k}

Observe that

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When we multiply these by 8-9x,

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and the sum of these terms is

\dfrac{56}3 x^2 - 21x^2 = \boxed{-\dfrac73 x^2}

2. The binomial expansion is

\left(2a - \dfrac b2\right)^8 = \displaystyle \sum_{k=0}^8 \binom 8k (2a)^{8-k} \left(-\frac b2\right)^k = \sum_{k=0}^8 \binom 8k 2^{8-2k} a^{8-k} b^k

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