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3 years ago

Need help with this , answers by morning ??

Chemistry

1 answer:

Svetach [21]3 years ago

4 0

275 mm = 27.5 cm
45mg = 4.5g
25cm = 250 mm
Not sure about number 8

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A compound made of two elements, iridium (Ir) and oxygen (O), was produced in a lab by heating iridium while exposed to air. The

natima [27]

1) Compund Ir (x) O(y)

2) Mass of iridium = mass of crucible and iridium - mass of crucible = 39.52 g - 38.26 g = 1.26 g

3) Mass of iridium oxide = mass of crucible and iridium oxide - mass of crucible = 39.73g - 38.26g = 1.47g

4) Mass of oxygen = mass of iridum oxide - mass of iridium = 1.47g - 1.26g = 0.21g

5) Convert grams to moles

moles of iridium = mass of iridium / molar mass of iridium = 1.26 g / 192.17 g/mol = 0.00656 moles

moles of oxygen = mass of oxygen / molar mass of oxygen = 0.21 g / 15.999 g/mol = 0.0131

6) Find the proportion of moles

Divide by the least of the number of moles, i.e. 0.00656

Ir: 0.00656 / 0.00656 = 1

O: 0.0131 / 0.00656 = 2

=> Empirical formula = Ir O2 (where 2 is the superscript for O)

Answer: Ir O2

5 0

4 years ago

Read 2 more answers

The head loss in a turbulent flow in a pipe varies Approximant as square of velocity • Direct as the velocity • Invers as square

Eddi Din [679]

Answer:

Head loss in turbulent flow is varying as square of velocity.

Explanation:

As we know that head loss in turbulent flow given as

$h_F=\dfrac{FLV^2}{2gD}$

Where

F is the friction factor.

L is the length of pipe

V is the flow velocity

D is the diameter of pipe.

So from above equation we can say that

$h_F\alpha V^2$

It means that head loss in turbulent flow is varying as square of velocity.

We know that loss in flow are of two types

1.Major loss :Due to surface property of pipe

2.Minor loss :Due to change in momentum of fluid.

5 0

3 years ago

Read 2 more answers

As an athlete exercises, sweat is produced and evaporated to help maintain a proper body temperature. On average, an athlete los

dmitriy555 [2]

<u>Answer:</u> For the given amount of sweat lost, the amount of energy required will be 692,899 Joules.

<u>Explanation:</u>

We are given:

Heat of vaporization for water = 2257 J/g

Amount of sweat lost = 307 grams

Applying unitary method:

For 1 g of sweat lost, the energy required is 2257 Joules

So, for 307 grams of sweat lost, the energy required will be = $\frac{2257J}{1g}\times 307g=692,899J$

Hence, for the given amount of sweat lost, the amount of energy required will be 692,899 Joules.

7 0

3 years ago

Please help!

Len [333]

It will slowly rotten and turn brown

7 0

4 years ago

How many moles of C3H8 will be produced from 75 moles of CO2?C3H8 + 5 O2 → 3 CO2 + 4 H2O

levacccp [35]

25 moles of C3H8 will be produced from 75 moles of CO2.

<h3>Mole calculation</h3>

To find the value of moles of a product from the number of moles of a reactant, it is necessary to observe the stoichiometric ratio between them:

$C_3H_8 + 5 O_2 = > 3 CO_2 + 4 H_2O$

Analyzing the reaction, it is possible to see that the stoichiometric ratio is 1:3, so we can perform the following expression:

C3H8 CO2

$\frac{1mol}{xmol} =\frac{3mol}{75mol}$

$x = 25mol$

So, 25 moles of C3H8 will be produced from 75 moles of CO2.

Learn, more about mole calculation in: brainly.com/question/2845237

8 0

2 years ago