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denis23 [38]
3 years ago
8

How many neutrons does an element have if its atomic number is 40 and its mass number is 154

Chemistry
1 answer:
kramer3 years ago
4 0
I am not sure about this answer 194
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Which of the changes gas to solid gas to liquid, liquid to solid liquid to gas,solid to liquid solid to gas will involve an outp
Verdich [7]

Answer:

Liquid to solid liquid to gas

Explanation:

Boiling a liquid result in a gas

7 0
2 years ago
Consider the chemical reaction represented below. CH4 + 2O2 CO2 + 2H2O + Heat Which of the following statements about this react
dsp73
A. the reaction releases heat
6 0
3 years ago
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1 point<br> How many moles of CO2 are there in 100.0 grams of CO2?
VikaD [51]

44.0095 you're welcome hope this helps

3 0
3 years ago
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A cylinder of compressed gas has a volume of 350 ml and a pressure of 931 torr. What volume in Liters would the gas occupy if al
hodyreva [135]

Answer:

0.384\ \text{L}

Explanation:

P_1 = Initial pressure = 931 torr = 931\times \dfrac{101.325}{760}=124.12\ \text{kPa}

P_2 = Final pressure = 113 kPa

V_1 = Initial volume = 350 mL

V_2 = Final volume

From the Boyle's law we have

P_1V_1=P_2V_2\\\Rightarrow V_2=\dfrac{P_1V_1}{P_2}\\\Rightarrow V_2=\dfrac{124.12\times 350}{113}\\\Rightarrow V_2=384.44\ \text{mL}=0.384\ \text{L}

The volume the gas would occupy is 0.384\ \text{L}.

3 0
2 years ago
A disk of radius 2.0 cm has a surface charge density of 6.3 μC/m2 on its upper face. What is the magnitude of the electric field
maksim [4K]

Answer:

the electric field at Z = 12 cm is E =   9.68 × 10³ N/C = 9.68 kN/C

Explanation:

Given: radius of disk, R = 2.0 cm = 2 × 10⁻² cm, surface charge density,σ = 6.3 μC/m² = 6.3 × 10⁻⁶ C/m², distance on central axis, z = 12 cm = 12 × 10⁻² cm.

The electric field, E at a point on the central axis of a charged disk is given by E = σ/ε₀(1 - \frac{z}{\sqrt{z^{2} + R^{2} }  })

Substituting the values into the equation, it becomes

E = σ/ε₀(1 - \frac{z}{\sqrt{z^{2} + R^{2} }  }) = 6.3 × 10⁻⁶/8.854 × 10⁻¹²(1 - \frac{0.12}{\sqrt{0.12^{2} + 0.02^{2} } }) = 7.12 × 10⁵(1 - \frac{0.12}{0.1216}) = 7.12 × 10⁵(1 - 0.9864) = 7.12 × 10⁵ × 0.0136 = 0.0968 × 10⁵ = 9.68 × 10³ N/C = 9.68 kN/C

Therefore, the electric field at Z = 12 cm is E =   9.68 × 10³ N/C = 9.68 kN/C

7 0
3 years ago
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