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Rina8888 [55]
3 years ago
13

What mass of carbon dioxide is formed when 1.75 mol of ethane burns completely in oxygen?

Chemistry
1 answer:
dybincka [34]3 years ago
3 0

Answer:

There is a mass of 154 Grams of Carbon Dioxide.

Explanation:

One mole is equal to 6.02 × 10^23 particles.

This means we have 1.05 X 10^24 total particles of Ethane.

Each ethane particle contains 2 carbon atoms.

If every particle of ethane is burned, we will end up with 2.10 x 10^24 molecules of Carbon Dioxide (Particles of Methane x 2, since each Methane particle contains 2 carbon atoms)

Carbon Dioxide has a molar mass of 44.01 g/mol

So if we take our amount of Carbon Dioxide molecules and divide it by 1 mole, ((2.10 x 10^24)/(6.02 x 10^23) = 3.49) we find that we have 3.49 moles of Carbon Dioxide.

Now all we need to do is multiply our moles of carbon dioxide(3.49) by it's molar mass(44.01) while accounting for significant digits.

What you should end up with is 154 Grams of Carbon Dioxide.

Hope this helps (And more importantly I hope I didn't make any errors in my math lol)

As a side note this is all assuming that this takes place at STP conditions.

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Explanation:

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For a compound to form two elements must combine in a definite order to given  single product.

The combination is facilitated by a loss, gain or sharing of electrons between two species. This leads to an attraction between the combining species.

Both Sodium and potassium would prefer to lose electrons and there is no reason for them to combine to form a compound.

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Undergoing an alpha decay will decrease the atomic mass by four and the atomic number by two.

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Explanation:

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