Use the following equation to answer the questions below.

Which of the following is not a landform?<br> A. Canyon<br> B. Plateau<br> C. Bay<br> D. Earthquake

kaheart [24]

D. Earthquake

This is because all the others are landforms.

5 0

3 years ago

The Lewis structure of N2H2 shows ________. Group of answer choices a nitrogen-nitrogen single bond each hydrogen has one nonbon

LenKa [72]

Answer:

one bond between nitrogen and hydrogen and a double bond between the nitrogen atoms.

Explanation:

H-N=N-H

7 0

3 years ago

Assuming equal concentrations and complete dissociation, rank these aqueous solutions by their freezing points from highest to l

muminat

Answer:

NH4Cl > Li2SO4 > CoCl3

Explanation:

Let us recall that the freezing point depression depends on the molality of the solution and the number of particles present.

Let us also recall that freezing point depression is a colligative property. It depends on the number of particles present in solution.

Usually, the more the number of particles present, the lower the freezing point. Hence, NH4Cl which has only two particles will have the highest freezing point while CoCl3 which has four particles will have the lowest freezing point.

4 0

3 years ago

Glucose (C6H12O6)(C6H12O6) can be fermented to yield ethanol (CH3CH2OH)(CH3CH2OH) and carbon dioxide (CO2).

zhenek [66]

Answer: a) 49.8 gram

b) 47.0 %

Explanation:

First we have to calculate the moles of glucose

$\text{Moles of glucose}=\frac{\text{Mass of glucose}}{\text{Molar mass of glucose}}=\frac{97.5g}{180.15g/mole}=0.54moles$

The balanced chemical reaction will be,

$C_6H_{12}O_6\rightarrow 2CH_3CH_2OH+2CO_2$

From the balanced reaction, we conclude that

As,1 mole of glucose produce = 2 moles of ethanol

So, 0.54 moles of glucose will produce = $\frac{2}{1}\times 0.54=1.08$ mole of ethanol

Now we have to calculate the mass of ethanol produced

$\text{Mass of ethanol}=\text{Moles of ethanol}\times \text{Molar mass of ethanol}$

$\text{Mass of ethanol}=(1.08mole)\times (46.08g/mole)=49.8g$

Now we have to calculate the percent yield of ethanol

$\%\text{ yield of ethanol}=\frac{\text{Actual yield}}{\text{Theoretical yield }}\times 100=\frac{23.4g}{49.8g}\times 100=47.0\%$

Therefore, the percent yield is 47.0 %

7 0

3 years ago

Calculate ΔGrxn at 298 K under the conditions shown below for the following reaction.

algol13

Answer : The value of $\Delta G_{rxn}$ is -24.9 kJ/mol

Explanation :

First we have to calculate the value of 'Q'.

The given balanced chemical reaction is,

$Fe_2O_3(s)+3CO(g)\rightarrow 2Fe(s)+3CO_2(g)$

The expression for reaction quotient will be :

$Q=\frac{(p_{CO_2})^3}{(p_{CO})^3}$

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

$Q=\frac{(2.1)^3}{(1.4)^2}$

$Q=3.375$

Now we have to calculate the value of $\Delta G_{rxn}$ .

The formula used for $\Delta G_{rxn}$ is:

$\Delta G_{rxn}=\Delta G^o+RT\ln Q$ ............(1)

where,

$\Delta G_{rxn}$ = Gibbs free energy for the reaction = ?

$\Delta G_^o$ = standard Gibbs free energy = -28.0 kJ/mol

R = gas constant = $8.314\times 10^{-3}kJ/mole.K$

T = temperature = 298 K

Q = reaction quotient = 3.375

Now put all the given values in the above formula 1, we get:

$\Delta G_{rxn}=(-28.0kJ/mol)+[(8.314\times 10^{-3}kJ/mole.K)\times (298K)\times \ln (3.375)$

$\Delta G_{rxn}=-24.9kJ/mol$

Therefore, the value of $\Delta G_{rxn}$ is -24.9 kJ/mol

5 0

3 years ago