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Keith_Richards [23]
3 years ago
6

How many kilojoules of heat are produced when 34.0 g of Fe2O3 reacts with an excess of CO according to the following reaction? F

e2O3 + 3 CO 2 Fe + 3 CO2 ΔH = -26.3 kJ
Chemistry
1 answer:
UkoKoshka [18]3 years ago
3 0

The heat produced when iron oxide reacts with carbon monoxide is -23.47 kJ/mol.

<h3>What is the enthalpy of reaction?</h3>

The standard enthalpy of the reaction is given by the enthalpy of formation of the products and the reactants. The reactants and the products of the reaction are:

Fe₂O₃ (s) + 3CO (g) → 2Fe(s) + 3CO₂ (g)

We know,

The standard enthalpy of formation of iron oxide = −825.50 kJ/mol

The standard enthalpy of formation of carbon monoxide = −110.53 kJ/mol

The standard enthalpy of formation of carbon dioxide = −393.52 kJ/mol

The standard enthalpy of reaction is calculated as:

\rm \Delta H_{rxn} = [2(0) + 3(−393.52)] - [1(-825.50) + 3(-110.53)]

= (0−1180.56+825.50+331.59)

= −23.47 kJ/mol

Therefore, −23.47 kJ/mol is produced.

Learn more about enthalpy here:

brainly.com/question/17204870

#SPJ1

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NNADVOKAT [17]

Answer:

it's just like doing a test grade on children if you give them different tests they might not come up with the same results, the molecules need to be the same or else the experiment will be even.

Explanation:

whenever water is hot the molecules will bounce really fast in the bottle, whenever water is cold he will go really slow in the bottle

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1.what happens in the nucleus of an atom when an alpha particle is emitted?
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What volume (ml) of fluorine gas is required to react with 1. 28 g of calcium bromide to form calcium fluoride and bromine gas a
Alexandra [31]

144 mL of fluorine gas is required to react with 1.28 g of calcium bromide to form calcium fluoride and bromine gas at STP.

<h3>What is Ideal Gas Law ? </h3>

The ideal gas law states that the pressure of gas is directly proportional to the volume and temperature of the gas.

PV = nRT

where,

P = Presure

V = Volume in liters

n = number of moles of gas

R = Ideal gas constant

T = temperature in Kelvin

Here,

P = 1 atm  [At STP]

R = 0.0821 atm.L/mol.K

T = 273 K  [At STP]

Now first find the number of moles

F₂  +  CaBr₂  →  CaF₂  +  Br₂

Here 1 mole of F₂ reacts with 1 mole of CaBr₂.

So,  199.89 g CaBr₂ reacts with  = 1 mole of F₂

1.28 g of CaBr₂ will react with = n mole of F₂

n = \frac{1.28\g \times 1\ \text{mole}}{199.89\ g}

n = 0.0064 mole

Now put the value in above equation we get

PV = nRT

1 atm × V = 0.0064 × 0.0821 atm.L/mol.K × 273 K

V = 0.1434 L

V ≈ 144 mL

Thus from the above conclusion we can say that 144 mL of fluorine gas is required to react with 1.28 g of calcium bromide to form calcium fluoride and bromine gas at STP.

Learn more about the Ideal Gas here: brainly.com/question/20348074

#SPJ4

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2 years ago
In a chemical reaction, which are the most likely products of these reactants 4Fe+302
Cerrena [4.2K]

2Fe2O3, reason is when we add 4Fe + 3O2, we get the same answer, but in a different form.

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