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2 years ago

12

Can someone help me PLEASE

1 answer:

AVprozaik [17]2 years ago

3 0

Lattice energy k bye

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As we move UP a energy pyramid, the amount of energy available to each level of consumers

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3 years ago

Which of the following is an example of symbiosis?

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D. One chimp cleaning and grooming the hair of another chimp

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3 years ago

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Compare and contrast an earthquake and a tsunami. Include one way they are similar and two ways they are different.

Anon25 [30]

One way they are similar is because an earthquake causes a tsunami so they are connected. two ways they are not is because ones dealing with water and ones dealing with land, and an earthquake is very sudden while a tsunami, you know its coming and you have time to move.

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3 years ago

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3 years ago

Carbon-14 is a radioactive isotope that decays according to first-order kinetics in a process that has a half-life of 5730 years

Sliva [168]

Answer : The time passed in years is $2.83\times 10^3\text{ years}$

Explanation :

Half-life = 5730 years

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{5730\text{ years}}$

$k=1.21\times 10^{-4}\text{ years}^{-1}$

Now we have to calculate the time passed.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $1.21\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = ?

a = let initial amount of the reactant = X g

a - x = amount left after decay process = $71\% \times (x)=\frac{71}{100}\times (X)=0.71Xg$

Now put all the given values in above equation, we get

$t=\frac{2.303}{1.21\times 10^{-4}}\log\frac{X}{0.71X}$

$t=2831.00\text{ years}=2.83\times 10^3\text{ years}$

Therefore, the time passed in years is $2.83\times 10^3\text{ years}$

8 0

3 years ago