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Alecsey [184]
3 years ago
15

imagine a drop of water hanging from your finger. how is this similar to the water staying together after the balloon is popped

Chemistry
1 answer:
stiv31 [10]3 years ago
3 0
The meniscus on your fingy is comparable to that of a bursted balloon

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Small bodies from which the planets formed
Aleks [24]
Small bodies from which the planets are formed is called : Planetesimal.
Planetesimals that have survived to the current day are valuable to scientists since they contain information about the Solar System's formation.
7 0
3 years ago
Read 2 more answers
What is the isotope notation for an ion of silver-109 with a charge of positive 1
Arisa [49]

Answer:

The isotope notation for an ion of silver-109 with a charge of positive 1 is _{47}^{109}Ag^{1+}.

Explanation:

The elements with same atomic number with different mass numbers are called isotopes.

The isotopes of silver is as follows.

_{47}^{109}Ag,_{47}^{107}Ag

From the above two isotopes have same atomic number and different mass number.

From the given,the isotope notation for an ion of silver-109 with a charge of positive 1

It can be represented is as follows.

_{47}^{109}Ag^{1+}

General representation of isotope is as in attachment.

6 0
3 years ago
What is N for ClO3, the<br>chlorate ion?<br>​
Kaylis [27]

Answer:

Explanation: There is no molecule or ion as ClO3. The correct formula of chlorate ion is ClO3-. bolivianouft and 4 more users found this answer helpful.

Explanation:

4 0
3 years ago
Iodine-131 half life 8.040 how long will it take for a 40 gram sample of iodine-131 to decay to 0.75 grams
otez555 [7]

Answer:

See explanation below

Explanation:

To get this, we need to apply the general expression for half life decay:

N = N₀e(-λt)    (1)

Where:

N and N₀ would be the final and innitial quantities, in this case, masses.

t: time required to decay

λ: factor related to half life

From the above expression we need λ and t. To get λ we use the following expression:

λ = t₁₂/ln2   (2)

And we have the value of half life, so, replacing we have:

λ = 8.04 / ln2 = 11.6

Now, we can replace in (1) and then, solve for t:

0.75 = 40 exp(-11.6t)

0.75 / 40 = exp(-11.6t)

ln(0.01875) = -11.6t

-3.9766 = -11.6t

t = -3.9766 / -11.6

<h2>t = 0.34 days</h2><h2></h2>
3 0
3 years ago
When 2-heptyne was treated with aqueous sulfuric acid containing mercury(II) sulfate, two products, each having the molecular fo
xeze [42]

Answer:

See explanation below

Explanation:

This is a reaction of alkyne hydration. We have aqueous sulfuric acid in HgSO4. This reagent is used to convert a alkyne into a ketone. The mechanism of reaction is taking place in 4 steps.

The first step is an electrophilic adition where the atom of Hydrogen that the acid provides, is added to the alkyne in the triple bond.

In this step, as Carbon 2 and Carbon 3, do not have any atom of hydrogen, the adition of this hydrogen could take place in either carbon 2 or carbon 3, that's why at the end you can have two products in equal amounts.

The second step is the adition of one molecule of water in the carbocation that appears in the previous step.

The third step, is an acid base equilibrium, where the hydrogen atom from the water that added to the heptene, is substracted (In this case by the conjugate base of the acid).

In this way, we will have an alcohol with a double bond. This is the enolic form of the molecule.

The final step is a tautomeric equilibrium, where the double bond of the C = C will pass to a double bond C = O forming a carbonile and therefore, a ketone.

If this was done in carbon 2 from step 1, you'll have the 2-heptanone. If it were on carbon 3, it will be the 3 - Heptanone.

Picture attached has the mechanism and products.

3 0
3 years ago
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