The gas will occupy 120 L at STP.
We can use the <em>Combined Gas Laws</em>
.
In 1982, chemists redefined <em>STP</em> as <em>1 bar</em> and 0 °C (273.15 K).
<em>p</em>_1 = 5100 mmHg × (1 atm/760 mmHg) × (1.013 bar/1 atm) = 6.798 bar
<em>T</em>_1 = (29 + 273.15) K = 302.15 K
<em>p</em>_1<em>V</em>_1/<em>T</em>_1 = <em>p</em>_2<em>V</em>_2/<em>T</em>_2
<em>V</em>_2 = <em>V</em>_1 × <em>p</em>_1/<em>p</em>_2 × <em>T</em>_2/<em>T</em>_1
= 20.1 L × (6.798 bar/1 bar) × (273.15 K/302.15 K) = 120 L
The answer is 40.5.
Standard form is in answered or not in a different form.
So, you must solve this.
4.05 * 10 = 40.5
Have a great day :) Let me know if you need help with anything else!
Answer:
200 g of NaOH
Explanation:
For this solution of NaOH
2.50 M means that in 1L of solution, we have 2.5 moles
Mol . molar mass = Mass
2.5 m . 40 g/m = 100 grams
In 1 L, we have 100 grams of solute, so in 2L, we have the double
200 g of NaOH
3
H
1
Upper left of chemical symbol= mass number
Lower left= atomic number
Answer:
Fe^2+(aq) + S^2-(aq) --------> FeS(s)
Explanation:
First let us look at the molecular equation;
Na2S(aq) + Fe(NO3)2(aq) --------> FeS (s) + 2NaNO3(aq)
Now, the net ionic equation usually shows the most important reaction that took place, in this case, the formation of the FeS precipitate.
Hence, ionically;
Fe^2+(aq) + S^2-(aq) --------> FeS(s)
