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masya89 [10]
3 years ago
15

I need help with that box

Chemistry
1 answer:
valkas [14]3 years ago
6 0

I hope this helps.

the first line would be SN, 50, 50, 69

second line would be PT, 78, 78, 117

third line would be MO, 42, 42, 54

fourth line would be NI, 28, 28, 31

fifth line would be U, 92, 92, 146

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Which ions aren't shown in net ionic reactions, because they are present as both reactants and products of the reaction, so they
Anvisha [2.4K]

Explanation:

This is correct!

Ions that exist in both the reactant and product side of the equation are referred to as spectator ions. Overall, they do not partake in the reaction. If they are present on both sides of the equation, you can cancel them out.

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Na+(aq) + Cl​−​​(aq) + Ag​+(aq) + NO​3​−​​(aq) → Na​+​​(aq) + NO​3​−​​(aq) + AgCl(s)

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7 0
3 years ago
Find the mass in 2.6 mole of lithium bromide
Tresset [83]

Answer:

2.6 mole of lithium bromide have 225.81 g.

Explanation:

Given data:

Number of moles of lithium bromide = 2.6 mol

Mass of lithium bromide = ?

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Formula:

<em>Number of moles = mass/ molar mass</em>

Molar mass of lithium bromide = 86.85 g/mol

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Thus 2.6 mole of lithium bromide have 225.81 g.

5 0
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