I need help with that box

Chemistry

1 answer:

valkas [14]3 years ago

6 0

I hope this helps.

the first line would be SN, 50, 50, 69

second line would be PT, 78, 78, 117

third line would be MO, 42, 42, 54

fourth line would be NI, 28, 28, 31

fifth line would be U, 92, 92, 146

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3. How much energy is needed to raise 45 grams of water from 40°C to 115 °C?

Dafna1 [17]

Answer:

Q = 114349.5 J

Explanation:

Hello there!

In this case, since this a problem in which we need to calculate the total heat of the described process, it turns out convenient to calculate it in three steps; the first one, associated to the heating of the liquid water from 40 °C to 100 °C, next the vaporization of liquid water to steam at constant 100 °C and finally the heating of steam from 100 °C to 115 °C. In such a way, we calculate each heat as shown below:

$Q_1=45g*4.18\frac{J}{g\°C}*(100\°C-40\°C)=11286J\\\\Q_2=45g* 2260 \frac{J}{g} =101700J\\\\Q_3=45*2.02\frac{J}{g\°C}*(115\°C-100\°C)=1363.5J$