The formula for Cs and S is Cs₂S.
For Cs and S,
Ions formed will be Cs⁺ and S²⁻
As cesium belongs to group 1A and sulfur belongs to group 6A. Therefore, the condensed electronic configuration is -
For Cs is [Xe} 6s¹ and for S is [Ne] 3s²3p⁴.
Cs have 1 valence electron and S have 6 valence electrons.
Hence to attain a stable electronic configuration, both two Cs atoms lose one electron and form Cs⁺ and these two electrons will be accepted by one S atom to form S²⁻.
Therefore the formula for the compound is Cs₂S as Cs donate 1 electron and S will accept 2 electrons from Cs.
The formula is Cs₂S.
To learn more about electronic configuration, visit: brainly.com/question/15051483
#SPJ4
I believe the answer in an inclined plane, because the ridge running along the sides run up the core. (Also, the other two answers are incorrect, so process of elimination)
Explanation:
- As it is given that boiling point of propanamide is very high. So, reason for this is that easy formation of hydrogen bonds which are strong enough that we have to provide large amount of heat to break it.
As in
, the hydrogen atoms which are present are positive in nature. Due to this they are able to form hydrogen bonds with the neighboring oxygen atom.
Hence, these bonds are so strong that high heat needs to given to break them.
- A propanoic acid contain carboxylic group as the functional group. So, this group is also able to form hydrogen bonding as it forms a hydrogen bond between an acid group and hydroxyl group of neighboring molecule.
Hence, it will also require high heat to break the bond due to which there will be increase in boiling point.
- In propanal, there is presence of aldehyde functional group and three carbon atoms chain which will not form strong bonding with the hydrogen atom of CHO. Due to this there will exist weak Vander waal's force that is not at all strong enough.
As a result, less energy will be needed to break the bonds in propanal. Hence, it has very low boiling point.
Yep ur right it’s b as it is balanced