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3 years ago

I need help with that box

Chemistry

1 answer:

valkas [14]3 years ago

6 0

I hope this helps.

the first line would be SN, 50, 50, 69

second line would be PT, 78, 78, 117

third line would be MO, 42, 42, 54

fourth line would be NI, 28, 28, 31

fifth line would be U, 92, 92, 146

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creativ13 [48]

The answer is E. coli

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3 years ago

Object A has a mass of 3,600 kilograms. Object B has a mass of 600 kilograms. The weight of Object B will be ________ times the

Natalija [7]

Hi the answer is 1/6, because 1/6 of 3,600 is 600, so it's 1/6. Have a great day!

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3 years ago

Explain why aluminum does not react with potassium nitrate (KNO3) although it reacts with copper nitrate

Ratling [72]

Answer:

Potassium is more reactive than aluminium, so no reaction takes place. But aluminium is more reactive than copper, so it replaces the copper in copper nitrate

<h3>Explanation:</h3>

More reactive metal compound + less reactive metal

-> no reaction

However

Less reactive metal compound + more reactive metal

-> more reactive metal compound + less reactive metal

This is called substitution reaction where the more reactive metal replaces the less reactive metal in the compound.

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2 years ago

True or False: The particles in the GASEOUS state are the furthest apart

tatyana61 [14]

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4 0

3 years ago

What element has 80 protons, 81 neutrons, 79 electrons?

Mariana [72]

Answer:

The element will be $^{161}_{80}X$

Explanation:

Given that,

Number of proton = 80

Number of neutron = 81

Number of electron = 79

We know that,

The atomic number is equal to the number of proton.

So, the atomic number is 80.

According to atomic number,

The element will be mercury.

We need to calculate the atomic mass

Using formula of atomic mass

$atomic\ mass=atomic\ number+number\ of\ neutron$

Put the value into the formula

$atomic\ mass=80+81$

$atomic\ mass=161$

We need to find the element

Using atomic mass and atomic number

$atomic\ mass\ number A=161$

$atomic\ number Z=80$

So, the element will be

$^{A}_{Z}X$

Put the value of A and Z

Hence, The element will be $^{161}_{80}X$

5 0

3 years ago