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Katen [24]
2 years ago
15

1.what happens in the nucleus of an atom when an alpha particle is emitted?

Chemistry
2 answers:
Vanyuwa [196]2 years ago
8 0

Answer: 1. The mass number is reduced by 4 units and atomic number is reduced by 2 units

2. Mass number remains same but the atomic number is increased by 1.

Explanation:

Alpha Decay: In this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. The mass number is reduced by 4 units and atomic number is reduced by 2 units.

_A^Z\textrm{X}\rightarrow _{A-2}^{Z-4}+_2^4\alpha

Beta Decay : It is a type of decay process, in which a proton gets converted to neutron and an electron. This is also known as \beta ^--decay. In this the mass number remains same but the atomic number is increased by 1.

_A^Z\textrm{X}\rightarrow _{A+1}^Z\textrm{Y}+_{-1}^0e

coldgirl [10]2 years ago
7 0
1) The nucleus of an atom loses 2 protons and 4 neutrons.
2) The nucleus of an atom gains a proton and it's neutrons remain the same.
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238 93 Np → 0 -1 e+ ?​
Sergeeva-Olga [200]

Answer:

²³⁸₉₃Np  → Pu₉₄²³⁸ + ⁰₋₁e

Explanation:

²³⁸₉₃Np  → Pu₉₄²³⁸ + ⁰₋₁e

Beta radiations:

Beta radiations are result from the beta decay in which electron is ejected. The neutron inside of the nucleus converted into the proton an thus emit the electron which is called β particle.

The mass of beta particle is smaller than the alpha particles.

They can travel in air in few meter distance.

These radiations can penetrate into the human skin.

The sheet of aluminium is used to block the beta radiation

⁴₆C → ¹⁴₇N + ⁰₋₁e

The beta radiations are emitted in this reaction. The one electron is ejected and neutron is converted into proton.

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3 years ago
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4 0
2 years ago
Read 2 more answers
combustion analysis of a hydrocarbon produced 33.01g CO2 and 13.51g H2O. Calculate the empirical formula for the hydrocarbon
masya89 [10]

Answer:

\rm CH_2.

Explanation:

Carbon and hydrogen are the only two elements in a hydrocarbon. When a hydrocarbon combusts completely in excess oxygen, the products would be \rm CO_2 and \rm H_2O. The \rm C and \rm H would come from the hydrocarbon, while the \rm O atoms would come from oxygen.

Look up the relative atomic mass of these three elements on a modern periodic table:

  • \rm C: 12.011.
  • \rm H: 1.008.
  • \rm O: \rm 15.999.

Calculate the molar mass of \rm CO_2 and \rm H_2O:

M(\mathrm{CO_2}) = 12.011 + 2 \times 15.999 = 44.009\; \rm g \cdot mol^{-1}.

M(\mathrm{H_2O}) = 2 \times 1.008 + 15.999 = 18.015\; \rm g \cdot mol^{-1}

Calculate the number of moles of \rm CO_2 molecules in 33.01\; \rm g of \rm CO_2\!:

\displaystyle n(\mathrm{CO_2}) = \frac{m(\mathrm{CO_2})}{M(\mathrm{CO2})} = \frac{33.01\; \rm g}{44.009\; \rm g\cdot mol^{-1}} \approx 0.7501\; \rm mol.

Similarly, calculate the number of moles of \rm H_2O molecules in 13.51\; \rm g of \rm H_2O\!:

\displaystyle n(\mathrm{H_2O}) = \frac{m(\mathrm{H_2O})}{M(\mathrm{H_2O})} = \frac{13.51\; \rm g}{18.015\; \rm g\cdot mol^{-1}} \approx 0.7499\; \rm mol.

Note that there is one carbon atom in every \rm CO_2 molecule. Approximately0.7501\; \rm mol of \rm CO_2\! molecules would correspond to the same number of \rm C atoms. That is: n(\mathrm{C}) \approx 0.7501\; \rm mol.

On the other hand, there are two hydrogen atoms in every \rm H_2O molecule. approximately 0.7499\; \rm mol of \rm H_2O molecules would correspond to twice as many \rm H\! atoms. That is: n(\mathrm{H}) \approx 2 \times 0.7499 \; \rm mol\approx 1.500\; \rm mol.

The ratio between the two is: n(\mathrm{C}): n(\mathrm{H}) \approx 1:2.

The empirical formula of a compound gives the smallest whole-number ratio between the elements. For this hydrocarbon, the empirical formula would be \rm CH_2.

6 0
3 years ago
Convert 7.50 mol of Li₂O to grams
Natali5045456 [20]

Answer:

223.5 g

Explanation:

The formula between the number of moles, mass and Mr can be used to convert moles to grams.

<em>Number of moles = mass ÷ Mr</em>

So, mass = number of moles × Mr

  Mr of Li₂O = (6.9 × 2) + 16 = 29.8

∴ Mass = 7.5 × 29.8 = <u>223.5 g</u>

4 0
2 years ago
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