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Ivenika [448]
2 years ago
14

The horizontal surface on which the block of mass 2.2 kg slides is frictionless. The force of 27 N acts on the block in a horizo

ntal direction and the force of 81 N acts on the block at an angle as shown below is the magnitude of the resulting ac celeration of the block? The acceleration of gravity is 9.8 m/s ^ 2
Physics
1 answer:
Digiron [165]2 years ago
7 0

The magnitude of the resulting acceleration of the block is 6.14 m/s².

The given parameters;

  • <em>mass of the block, m = 2.2 kg</em>
  • <em>horizontal force on the block, F = 27 N</em>
  • <em>force below the horizontal, 81 N at 60⁰</em>

The net horizontal force on the block is calculated as follows;

F_x = 27 \ -  81 \times cos (60)\\\\F_x = -13.5 \ N

The acceleration of the block is calculated as follows;

a = \frac{-13.5}{2.2} \\\\a = - 6.14 \ m/s^2\\\\a = 6.14 \ m/s^2 \ to \ the \ left

Thus, the magnitude of the resulting acceleration of the block is 6.14 m/s².

Learn more here:brainly.com/question/13707159

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At t=0, a block A of mass 8 kg and block B of mass 16 kg are both at position x=0 . Block A is at rest, and block B is moving at
love history [14]

The center of mass of the two objects is the average position of the parts of the two object system

The center of mass of block <em>A</em>, and block <em>B</em>  after displacement of block <em>B</em> is at <u>20 m from block </u><u><em>A</em></u>

<em />

Reason:

The given parameters are;

The position of block A and block B at t = 0 is x = 0

The mass of block A, m₁ = 8 kg

Mass of block B, m₂ = 16 kg

Speed of block <em>A</em> = 0 m/s

Speed of block <em>B</em>, v₂ = 10 m/s

Location of the center of mass of the two object at t = 3 s; Required

Solution;

The location of block <em>A</em>, after 3 s is x₁ = 0 (block A is at rest)

The location of block <em>B</em>, = v₂ × t

The location of block <em>B</em>, after 3 s is x₂ = 10 m/s × 3 s = 30 m

The center of mass of two masses are given as follows;

x_{cm} = \dfrac{m_1 \cdot x_1 +m_2\cdot x_2}{m_1 + m_2}

x_{cm} = \dfrac{8  \times0 + 16 \times  30}{8 + 16} = 20

The center of mass of the two objects is at at the position x = <u>20 m</u> (from block <em>A</em>)

Learn more about the center of mass here:

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4 0
3 years ago
In a shipping yard, a crane operator attaches a cable to a 1,400 kg shipping container and then uses the crane to lift the conta
Molodets [167]

Answer:

Explanation:

Given

mass of crane m=1400\ kg

distance moved d=40\ m

Since it is moving with a constant velocity therefore net force on it is zero

Tension force=weight

T=mg

Work done by Tension T is

W_T=T\cdot d

W_T=1400\times 9.8\cdot 40

W_T=548.8\ KJ

Work done by Gravity will be equal in magnitude but opposite in sign and can be obtained by work energy theorem which states that change in kinetic energy of object is equal to work done by all the forces

W_T+W_g=0

W_g=-548.8\ KJ

                                 

4 0
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Your friend is wearing a red coat. When white light hits the coat, some light is reflected, and some is absorbed.
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Answer:

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2 years ago
Which players are usually the tallest on their team, and stay close to the basket so they can shoot and rebound the ball?
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Answer:

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Explanation:

The center is the tallest player on each team, playing near the basket. On offense, the center tries to score on close shots and rebound. But on defense, the center tries to block opponents' shots and rebound their misses.

7 0
3 years ago
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