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2 years ago

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The horizontal surface on which the block of mass 2.2 kg slides is frictionless. The force of 27 N acts on the block in a horizo

ntal direction and the force of 81 N acts on the block at an angle as shown below is the magnitude of the resulting ac celeration of the block? The acceleration of gravity is 9.8 m/s ^ 2

1 answer:

Digiron [165]2 years ago

7 0

The magnitude of the resulting acceleration of the block is 6.14 m/s².

The given parameters;

<em>mass of the block, m = 2.2 kg</em>
<em>horizontal force on the block, F = 27 N</em>
<em>force below the horizontal, 81 N at 60⁰</em>

The net horizontal force on the block is calculated as follows;

$F_x = 27 \ - 81 \times cos (60)\\\\F_x = -13.5 \ N$

The acceleration of the block is calculated as follows;

$a = \frac{-13.5}{2.2} \\\\a = - 6.14 \ m/s^2\\\\a = 6.14 \ m/s^2 \ to \ the \ left$

Thus, the magnitude of the resulting acceleration of the block is 6.14 m/s².

Learn more here:brainly.com/question/13707159

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