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sveta [45]
2 years ago
15

What do the top of a zip line and the top of a bungee cord have in common

Physics
2 answers:
LiRa [457]2 years ago
6 0

Answer:

They are both placed at high vantage points for an optimal experience.

Explanation:

Gravity works in your favor when participating in bungee jumping as well as ziplining

Alisiya [41]2 years ago
5 0
They are both very high up
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When you hold a frozen banana treat in your hands, which statement BEST describes what is taking place? A. Heat is flowing from
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The answer is A

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It is A because your body heat is warmer than the banana and when you hold it the heat is transferring over.

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A ladder 7.85 m long leans against the side of a building. If the ladder is inclined at an angle of 79.5° to the horizontal, wha
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When temperature and pressure are applied to sedimentary and igneous rock?
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Igneous rock

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6 0
3 years ago
Explain the relationship between temperature, energy, and motion of particles in an object.
ANEK [815]

Answer:

Explanation:

Temperature is the degree of hotness or coldness of a body.

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Motion is the change in position of a body with time.

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7 0
3 years ago
A student throws a rock horizontally from the edge of a cliff that is 20 m high. The rock has an initial speed on 10 m/s. If air
fiasKO [112]

The distance of the rock from the base of the cliff is C) 20 m

Explanation:

The motion of the rock in this problem is a projectile motion, which consists of two independent motions:

- A uniform motion (constant velocity) along the horizontal direction

- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction

We start by analyzing the vertical motion to find the time of flight of the rock (the time it takes to reach the ground). We can do it by using the suvat equation:

s=u_y t+\frac{1}{2}at^2

where, taking downward as positive direction,

s = 20 m is the vertical displacement of the rock

u_y=0 is the initial vertical velocity

t is the time of flight

a=g=9.8 m/s^2 is the acceleration of gravity

Solving for t,

t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2(20)}{9.8}}=2.02 s

Now we can analzye the horizontal motion: the rock moves horizontally with a constant velocity of

v_x = 10 m/s

Therefore, the horizontal distance covered after a time t is

d=v_x t

and substituting t = 2.02 s, we find the final distance of the rock from the base of the cliff:

d=(10)(2.02)=20 m

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

6 0
3 years ago
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