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Alex_Xolod [135]

2 years ago

6

Dock walls sometimes have pillars replaced with rubber car tyres.explain how this reduces the possibility of damage what a boat

docks

1 answer:

ra1l [238]2 years ago

8 0

The rubber absorbs the kinetic energy from the impact of a boat hitting the tires

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WHICH SHOULD NOT BE PART OF SCIENTIFIC INQUIRY

umka21 [38]

Answer:

Not collecting the info

Explanation:

5 0

2 years ago

A basketball is shot from 2 meters up at an angle of 60° above the x axis at an initial velocity of 9 m/s. What is the maximum h

Nikitich [7]

Hope this helps a little

initial distance up = 2

initial velocity component up = 9 sin 60 = 7.79

v = 9 sin 60 - 9.8 t

when v = 0, we are there

9.8 t = 7.79

t = .795 seconds to top

h = 2 + 7.79(.795) - 4.9(.795^2)

7 0

3 years ago

Read 2 more answers

9. How does the length of the hypotenuse in a right triangle relate to the lengths of the legs? (2 points)

konstantin123 [22]

<span>The pythagorean theorem addresses the length of the hypotenuse in relation to the length of the legs. The square root of the length of the hypotenuse is equal to the sum of one leg squared plus the other leg squared. In other words, A squared plus B squared equals C squared where A and B are the lengths of the legs of the triangle and C is the length of the hypotenuse.</span>

6 0

2 years ago

Read 2 more answers

A 4.79 g bullet moving at 642.3 m/s penetrates a tree trunk to a depth of 4.35 cm. Use work and energy considerations to find th

vladimir1956 [14]

Answer:

Force, $F=2.27\times 10^4\ N$

Explanation:

Given that,

Mass of the bullet, m = 4.79 g = 0.00479 kg

Initial speed of the bullet, u = 642.3 m/s

Distance, d = 4.35 cm = 0.0435 m

To find,

The magnitude of force required to stop the bullet.

Solution,

The work energy theorem states that the work done is equal to the change in its kinetic energy. Its expression is given by :

$F.d=\dfrac{1}{2}m(v^2-u^2)$

Finally, it stops, v = 0

$F.d=-\dfrac{1}{2}m(u^2)$

$F=\dfrac{-mu^2}{2d}$

$F=\dfrac{-0.00479\times (642.3)^2}{2\times 0.0435}$

F = -22713.92 N

$F=2.27\times 10^4\ N$

So, the magnitude of the force that stops the bullet is $2.27\times 10^4\ N$

7 0

2 years ago

A projectile is fired directly upward from the ground with an initial velocity of 112 f/sec its distance s above the ground afte

Travka [436]

Answer:

3.48 seconds

Explanation:

At maximum height Vf=0 m/s

Vf= Vi - g*t

⇒g*t= Vi

⇒t= Vi/g

⇒t= 112/32.17 sec

⇒ t= 3.48 s

so the projectile will achieve its maximum height in 3.48 seconds.

7 0

2 years ago