Answer:
a = 64 ft / s²
Explanation:
The force in a spring is given by Hooke's law
F = -k x
Let's use the initial data to calculate the spring constant
k = F / x
Reduscate to the English system
x = 3 in (1foot/12 in) =0.25 foot
k = 0.3 / 0.25
k = 1.2 lb / foot
Now we can use Newton's second law
F = ma
a = F / m
a = -k x / m
m = w / g
m = 0.3 / 32 = 0.009375
x= 6 in (1foot /12 in)= 0.5 foot
a = - 1.2 0.5 / 0.009375
a = 64 ft / s²
Answers :
Explanation:
Given that.
First cylinder data
Inertial I₁ = 2.4 kgm²
angular speed ω₁ = 5.8 rad/s.
Second cylinder data
inertia I₂ = 1.3 kgm²
angular speed ω₂ = 7.0 rad/s.
If the cylinders couple so they have the same rotational axis, what is the angular speed of the combination (in rad/s)?
So, the cylinder couple and move together with the same angular speed
Then, using conservation of angular momentum
L(final) = L(initial)
(I₁ + I₂) • ω = I₁•ω₁ + I₂ω₂
(2.4+1.3)•ω = 2.4 × 5.8 + 1.3 × 7
3.7•ω = 23.02
ω = 23.02 / 3.7
ω = 6.22 rad/s
The combine angular speed of the cylinder is 6.22 rad/s
Answer:
i did not learn this yet im going into 6th grade im still in 5th
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