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2 years ago

What is the ph of a buffer that is 0. 08 m naa and 0. 1 ha. The ka of ha = 1. 0 x 10^-4

1 answer:

Crank2 years ago

4 0

Henderson-Hasselbalch equation relates the pH with the dissociation constant of the acid. The pH of the buffer solution will be 3.90.

<h3>What is the Henderson-Hasselbalch equation?</h3>

The Henderson-Hasselbalch equation is used to calculate the pH or the concentration of the conjugate base and acid.

The Henderson-Hasselbalch equation can be given as,

pH = pKa + log [A⁻] ÷ [HA]

The dissociation reaction is given as,

HA⁺ + H2O ⇌ H3O⁺ + A⁻

NaA → Na⁺ + A⁻

For this first pKa is calculated as:

pKa = - log (1. 0 x 10⁻⁴)

Substituting the value of pKa in Henderson-Hasselbalch equation pH is determined as:

pH = - log (1. 0 x 10⁻⁴) + log [0.08] ÷ [0.1]

= 4 + (-0.0969)

= 3.90

Therefore, 3.90 is the pH of the solution.

Learn more about Henderson-Hasselbalch here:

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