3 MgCl2 + 2 Al = 3 Mg + 2 AlCl3
Since we know that we have 12 moles of MgCl2 and enough Al, we don't need to figure out the exact amount of Al.
3 MgCl2 / 2 AlCl3 = 12 mol MgCl2 / x mol AlCl2
cross-multiply
3 MgCl2(x mol AlCl2) = 12 mol MgCl2(2 AlCl3)
3x = 24
x=8
8 moles AlCl3
Alternatively, we know that we have 12 moles of MgCl2, and a coefficient of 3. This indicates a multiplier of 4 for the entire equation, meaning 2 AlCl3 multiplied by (4) = 8 moles
<h3>Answer:</h3>
221.90 g.mol⁻¹
<h3>Explanation:</h3>
The mass of contained by a molecule is known as molecular mass. It is the sum of atomic weights of the elements contained by the molecule. In given case Iodine Pentafluoride has a chemical formula,
IF₅
The atomic weights of each element are as;
Iodine = 126.90 g.mol⁻¹
Fluorine = 19.00 g.mol⁻¹
As there are five atoms of Fluorine so, we will multiply the atomic weight of Fluorine by five and that of Iodine by one as there is only one Iodine atom.
Therefore,
Molecular Mass of IF₅ = (1 × 126.90 g.mol⁻¹) + (5 × 19.00 g.mol⁻¹)
Molecular Mass of IF₅ = (126.90 g.mol⁻¹) + (95.00 g.mol⁻¹)
Molecular Mass of IF₅ = 221.90 g.mol⁻¹
Anatomy I think it's important to know anatomy as a young adult so u are self aware of your body
Answer:
164
1st step we will write desperate molar mass of each element
