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SIZIF [17.4K]
3 years ago
15

How can a chemical reaction be sped up?Select from the drop-down menu to correctly complete the statement.

Chemistry
2 answers:
djyliett [7]3 years ago
5 0
The answer is : Concentration
And yes
lakkis [162]3 years ago
3 0

Answer:

A) Concentration

Explanation:

When you add a chemical to itself it becomes more concentrated making it more powerful and faster

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How many atoms are there in 48 grams of carbon?
d1i1m1o1n [39]

Answer:

20

Explanation:

3 0
2 years ago
Consider the reaction of A(g) + B(g) + C(g) => D(g) for whichthe following data were obtained:
AveGali [126]

Answer:

rate= k[A]²[B]²[C]

Explanation:

When concentration of A is increased two times ,keeping other's concentration constant , rate of reaction becomes 4 times .

So rate is proportional to [A]²

When concentration of B is increased two times , keeping other's concentration constant,rate of reaction becomes 4 times.

So rate is proportional to [B]²

When concentration of C is increased two times , keeping other's concentration constant, rate of reaction becomes 2 times.

So rate is proportional to [C]

So rate= k[A]²[B]²[C]

5 0
3 years ago
Percent Error Problems – Find the percent error for each problem below.
Citrus2011 [14]

% error = 3.4 %

Percent error = |accepted value - experimental value|/accepted value × 100%

∴ % error = |355 mL – 343 mL|/355 mL × 100 % = |12|/355 × 100 % = 3.4 %

5 0
3 years ago
Balance the Chemical Equations<br><br> MgF2 + Li2CO3---&gt; MgCO3 + LiF <br><br> Please Help
kirill115 [55]

Answer:

MgF2 + Li2CO3 ---> MgCO3 + 2LiF

Explanation:

4 0
3 years ago
What is the specific heat of a substance that absorbs 2500 joules of heat when a sample of 100g of the substance increases in te
Ierofanga [76]

Answer:

0.417 J/gºC

Explanation:

From the question given above, the following data were obtained:

Heat (Q) absorbed = 2500 J

Mass (M) of substance = 100 g

Initial temperature (T1) = 10 °C

Final temperature (T2) = 70 °C

Specific heat capacity (C) =?

Next, we shall determine the change in temperature (ΔT). This can be obtained as follow:

Initial temperature (T1) = 10 °C

Final temperature (T2) = 70 °C

Change in temperature (ΔT) =?

Change in temperature (ΔT) = T2 – T1

Change in temperature (ΔT) = 70 – 10

Change in temperature (ΔT) = 60 °C

Finally, we shall determine the specific heat capacity of the substance as follow:

Heat (Q) absorbed = 2500 J

Mass (M) of substance = 100 g

Change in temperature (ΔT) = 60 °C

Specific heat capacity (C) =?

Q = MCΔT

2500 = 100 × C × 60

2500 = 6000 × C

Divide both side by 6000

C = 2500 / 6000

C = 0.417 J/gºC

Therefore, the specific heat capacity of substance is 0.417 J/gºC

5 0
3 years ago
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