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Artemon [7]
2 years ago
11

Help i dont get it

Chemistry
1 answer:
Colt1911 [192]2 years ago
7 0

Answer:

2. Products; FeCl2 and H2S

Reactants; FeS and HCl

3. a) 36g of water

b) 64g of oxygen

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IgorLugansk [536]
Sodium has the greatest density at STP
6 0
3 years ago
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An equilibrium mixture of O2, SO2 and SO3 contains equal concentrations of SO2 and SO3.
AleksAgata [21]

Answer:

[O₂(g)] = 0.0037M

Explanation:

            2SO₂(g) + O₂(g) => 2SO₃(g)

Conc:   [SO₂(g)]   [O₂(g)]     [SO₃(g)]  and  [SO₂(g)] = [SO₃(g)]

Kc =  [SO₃(g)]²/[O₂(g)][SO₂(g)]² => Kc = 1/[O₂(g)] = 270 if [SO₂(g)] = [SO₃(g)]

∴ [O₂(g)] = (1/270)M = 0.0037M  

7 0
3 years ago
Which of the following is the correct name for the compound K2BrO2?
Zigmanuir [339]
The correct name for the molecular formula <span>K2BrO2 would be potassium bromine dioxide. In addition, one of the primary uses of this chemical compound would be in the water purifying, as well as in water treatment industry which could serve as an alternative to chlorine as a disinfectant.</span>
4 0
3 years ago
¿Por qué se dice que la Revolución Tecnológica de la segunda mitad del siglo XX está relacionada con el Física de la Materia Con
GREYUIT [131]

translate? ill edit this answer once it is

7 0
3 years ago
Your lab partner combined chloroform and acetone to create a solution where the mole fraction of chloroform, Xchloroform, is 0.1
jeyben [28]

Answer:

Explanation:

[u]Assumptions[/u]

1. There is exactly 1 mole of chloroform

2. The liquids mix together well such that the volume of the solution is the sum of the volumes of the two liquids

Given that the mole fraction of the Chloroform is 0.171

Mole fraction of Chloroform =

Mole of chloroform /(Mole of chloroform + mole of acetone)

According to assumptions, mole of chloroform is equal to 1

Therefore 0.171 =1/(1+mole of acetone)

1 + mole of acetone = 1/0.171

Mole of acetone = 1(/0.171) - 1

Moles of acetone = 4.85mol.

From Stochiometry

Mass of acetone = Mole of acetone * Molar Mass of acetone

Molar mass of acetone = 58.1grams/mol

Mass of acetone = 4.85 *58.1 = 282g =0.282kg

Mass of chloroform = moles of chloroform *Molar mass of Chloroform

Molar mass of chloform = 119.4 grams/mol

Mass of chloroform = 1* 119.4 =119.4g=0.1994kg

Volume of acetone = Mass of acetone / Density of acetone

Volume of acetone = 282/0.791

Volume of acetone = 357mL

Volume of Chloroform = Mass of Chloroform /Density of Chloroform

Volume of Chloroform = 119.4/1.48

= 81mL

Total volume of solution = 357mL+81mL = 438mL = 0.438L

1. Molarity = Moles of solute(chloroform)/mass of solvent (acetone) in kg

Molarity = 1/0.282 = 3.55molal

2. Molarity = moles of solute( chloroform) /Volume of solution

= 1/0.438 =2.28Molar

Therefore the molality and molarity respectively are 3.55 and 2.28.

4 0
3 years ago
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