Answer:
λ = 5.56 × 10⁻³ m
Explanation:
You have to use the formula c = λv to solve the problem. Review what you are given. You are given v and c, where v = 5.40 × 10¹⁰ Hz and c = 3.00 × 10⁸ m/s. The value c is for the speed of light and is something you need to memorize. You will use it often in physics and sometimes in chemistry.
Now that you figured out what you know, you can see that there is only one unknown, allowing you to solve.
c = λv
λ = c/v
λ = (3.00 × 10⁸ m/s)/(5.40 × 10¹⁰ Hz)
λ = 5.56 × 10⁻³ m
<u>Answer:</u> The volume of oxygen gas required is 3.75 mL
<u>Explanation:</u>
STP conditions:
1 mole of a gas occupies 22.4 L of volume.
We are given:
Volume of ammonia reacted = 3.00 mL = 0.003 L (Conversion factor: 1 L = 1000 mL)
The chemical equation for the reaction of ammonia with oxygen follows:
By Stoichiometry of the reaction:
(4 × 22.4) L of ammonia reacts with (5 × 22.4) L of oxygen gas
So, 0.003 L of ammonia will react with = 
of oxygen gas
Hence, the volume of oxygen gas required is 3.75 mL
Convert all of the units from centimeters to meters by moving the decimal point over to the left two digits.
0.15 m x 0.06 m x 0.12 m
Volume = length x width x height
= 0.15 x 0.06 x 0.12 = 0.00108 m^3
11 LIMITING react this is the answer
