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Kipish [7]
3 years ago
10

What is the configuration of electrons within an atom?

Chemistry
1 answer:
ivann1987 [24]3 years ago
4 0
Electron configuration is the distribution of electrons of an atom or molecule (or other physical structure) in atomic or molecular orbitals.[1] For example, the electron configuration of the neon atom is 1s2 2s2 2p6, using the notation explained below.
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For the reaction 2kclo3(s)→2kcl(s)+3o2(g) calculate how many grams of oxygen form when each quantity of reactant completely reac
barxatty [35]
First, we need to get the molar mass of:

KClO3 = 39.1 + 35.5 + 3*16 = 122.6 g/mol

KCl =39.1 + 35.5 = 74.6 g/mol

O2 = 16*2 = 32 g/mol

From the given equation we can see that:

every 2 moles of KClO3 gives 3 moles of O2

when mass = moles * molar mass

∴ the mass of KClO3 = (2mol of KClO3*122.6g/mol) = 245.2 g

and the mass of O2 then = 3 mol * 32g/mol = 96 g

so, 245.2 g of KClO3 gives 96 g of O2

A) 2.72 g of KClO3: 

when 245.2 KClO3 gives → 96 g  O2

   2.72 g KClO3 gives →  X

X = 2.72 g KClO3 * 96 g O2/245.2 KClO3

    = 1.06 g of O2

B) 0.361 g KClO3:

when 245.2 g KClO3 gives → 96 g O2

     0.361 g KClO3 gives → X

∴ X = 0.361g KClO3 * 96 g / 245.2 g

       = 0.141 g of O2

C) 83.6 Kg KClO3:

when 245.2 g KClO3 gives → 96 g O2

       83.6 Kg KClO3 gives  →  X

∴X = 83.6 Kg* 96 g O2 /245.2 g KClO3

     = 32.7 Kg of O2

D) 22.4 mg of KClO3:

when 245.2 g KClO3 gives → 96 g O2

        22.4 mg KClO3 gives → X

∴X = 22.4 mg * 96 g O2 / 245.2 g KClO3

      = 8.8 mg of O2

     

 


7 0
3 years ago
What is the maximum number of moles of NaCl that can be produced from the reaction of 5.6 mol Na and 4.7 mol CI2?
RideAnS [48]

Answer:

Explanation:

Na + Cl2 —> NaCl

8 0
2 years ago
How many grams of XeF6 are required to react with 0.579 L of hydrogen gas at 4.46 atm and 45°C in the reaction shown below?
natka813 [3]

Answer:

8.1433 g of XeF₆  are required.

Explanation:

Balanced chemical equation;

XeF₆ (s) + 3H₂ (g)   →  Xe (g) + 6HF (g)

Given data:

Volume of hydrogen = 0.579 L

Pressure = 4.46 atm

Temperature = 45 °C (45+273= 318 k)

Solution:

First of all we will calculate the moles of hydrogen

PV = nRT

n = PV/ RT

n = 4.46 atm × 0.579 L / 0.0821 atm. dm³. mol⁻¹. K⁻¹ × 318 K

n = 2.6 atm . L / 26.12 atm. dm³. mol⁻¹

n = 0.0995 mol

Mass of hydrogen:

Mass = moles × molar mass

Mass =  0.0995 mol × 2.016 g/mol

Mass =  0.2006 g

Now we will compare the moles of hydrogen with XeF₆ from balance chemical equation.

                                         H₂   :  XeF₆

                                          3    :    1

                                 0.0995   : 1/3× 0.0995 = 0.0332 mol

Now we will calculate the mass of XeF₆.

Mass = moles × molar mass

Mass = 0.0332 mol × 245.28 g/mol

Mass = 8.1433 g

4 0
3 years ago
A less-intense wave will have fewer _____ than a more-intense wave.
Shalnov [3]
A less intense wave will have fewer OSCILLATING AMPLITUDE than a more intense wave.
The intensity of a wave is the power transferred per unit area, where the area is measured on the plane perpendicular to the direction of propagation of the energy. Intense sounds are characterized by the particles of the medium vibrating back and forth with large amplitude.<span />
3 0
2 years ago
Read 2 more answers
Sodium chloride is produced from its elements
Kisachek [45]

Answer:

                     Mass of Sodium  =  574.75 g

                     Mass of Chlorine  =  886.25 g

Explanation:

                   The  balance chemical equation for the synthesis of NaCl is,

                                        2 Na + Cl₂ → 2 NaCl

Step 1: <u>Find out moles of each reactant required,</u>

According to balance chemical equation,

                 2 moles of NaCl is produced by  =  2 moles of Na

So,

         25 moles of NaCl will be produced by  =  X moles of Na

Solving for X,

                     X  =  25 mol × 2 mol /  2 mol

                     X  =  25 moles of Na

Similarly for Cl₂,

According to balance chemical equation,

                 2 moles of NaCl is produced by  =  1 mole of Cl₂

So,

         25 moles of NaCl will be produced by  =  X moles of Cl₂

Solving for X,

                     X  =  25 mol × 1 mol /  2 mol

                     X  =  12.5 moles of Cl₂

Step 2: <u>Convert each moles to mass as;</u>

Mass  =  Moles × Atomic Mass

For Na,

Mass  =  25 mol × 22.99 g/mol

Mass  =  574.75 g

For Cl₂,

Mass  =  12.5 mol × 70.90 g/mol

Mass  =  886.25 g

6 0
3 years ago
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