Sin³ x-sin x=cos ² x
we know that:
sin²x + cos²x=1 ⇒cos²x=1-sin²x
Therefore:
sin³x-sin x=1-sin²x
sin³x+sin²x-sin x-1=0
sin³x=z
z³+z²-z-1=0
we divide by Ruffini method:
1 1 -1 -1
1 1 2 1 z=1
-------------------------------------
1 2 1 0
-1 -1 -1 z=-1
--------------------------------------
1 1 0 z=-1
Therefore; the solutions are z=-1 and z=1
The solutions are:
if z=-1, then
sin x=-1 ⇒x= arcsin -1=π+2kπ (180º+360ºK) K∈Z
if z=1, then
sin x=1 ⇒ x=arcsin 1=π/2 + 2kπ (90º+360ºK) k∈Z
π/2 + 2kπ U π+2Kπ=π/2+kπ k∈Z ≈(90º+180ºK)
Answer: π/2 + Kπ or 90º+180ºK K∈Z
Z=...-3,-2,-1,0,1,2,3,4....
-2, 2 and for the other 4,5
Answer:


Step-by-step explanation:
we are given a vertex of a square i.e <u>(</u><u>1</u><u>,</u><u>1</u><u>)</u>
and the equations of the two parallel sides
notice that, the given vertex coordinates satisfy one of the parallel side i.e <u>y=</u><u>x </u>which means that (1,1) points lie on one of Parallel sides
remember that,
every angles of a square is <u>9</u><u>0</u><u>°</u><u> </u>
therefore,
we need to figure out the remaining <u>Perpendicular</u><u> </u><u>line </u><u> </u>of the given Parallel sides so
let's figure out the perpendicular line of y=x line
recall that,
Parallel lines have the same slope thus

since we are given a vertex the equation of the perpendicular line should be

distribute:

add 1 to both sides:

to figure out the second perpendicular line we can consider the coordinates (0.5,0.5) of y=x equation
so the slope of the perpendicular line is -1
and the equation:

distribute:

add 0.5 to both sides:

and we are done!
Simply get the product of 2 and 1/2 by 1/7.
firstly, let's convert the mixed fraction to "improper" and then multiply.