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Marat540 [252]
3 years ago
5

Starting with the number 100, Shaffiq repeatedly divides his number by two and then takes the greatest integer less than or equa

l to that number. How many times must he do this before he reaches the number 1?
Please don't answer unless you have the correct answer.
Mathematics
1 answer:
Artyom0805 [142]3 years ago
8 0
The answer is 6 times not 100% sure but I think it is
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carla's bead order includes 3 boxes of 100 beads. which could ve the number of beads in carla's order?
Stels [109]
The way you typed it, it seems like you need to know the total number of beads, which would be 300
8 0
3 years ago
Need help fast please
lesantik [10]

Answer:

D not here

Step-by-step explanation:

A-2 is not reasonable as it is not possible

C- bot possible

B- maybe

D- most reasonable

7 0
3 years ago
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The doubling time of a population of grasshoppers is 10 days. By what factor does the population of grasshoppers grow in 35 days
12345 [234]
So in 10 days the grasshopper (x) is doubled (2x)
20 days it is 2(2x) or 4x
30 days it is 2(4x) or 8x
in 35 days it is 1/2 of 10 so 1/2 times 2 times 8x=8x

it increased by a factor of 8
8 0
3 years ago
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Help please!<br><br> | 2x^2 + 5x + 3 | &gt; 0<br> solve the inequality
vovikov84 [41]

Factorize the quadratic.

2x^2 + 5x + 3 = (2x + 3) (x + 1)

We have |ab| = |a||b|, so

|2x^2 + 5x + 3| = |2x + 3| |x + 1| > 0

Now, both |2x+3|\ge0 and |x+1|\ge0 (since the absolute value of any number cannot be negative), so we just need to worry about when the left side is exactly zero. This happens for

(2x + 3) (x + 1) = 0 \implies 2x+3 = 0\text{ or }x+1 = 0 \\\\ \implies x = -\dfrac32 \text{ or } x = -1

So the solution to the inequality is the set

\left\{x \in \Bbb R \mid x\neq-\dfrac32 \text{ and } x\neq-1\right\}

3 0
2 years ago
The school is selling potted plants as a fundraiser.Kara sold 12 ferns and 8 ivy plants for $260.Paul sold 15 ivy plants and 6 f
vovangra [49]

x=ferns ; y=ivy

12x+8y=260

6x+15y=240

x=60 -(15/6)y

12(60+ (15/6)y + 8y = 260

x=60 -(15/6)y

720 - 30y + 8y = 260

x=60- (15/6)y

-30y +8y= 260-720 ==> -22y= -460

x=60 -(15/6)y

y= (-460)/(-22)= 20.9090909091

y=20.90

x=60 -(15/6)×20.90= 7.75

×(ferns)=7.75$

y(ivy)=20.90$

8 0
3 years ago
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