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Art [367]
2 years ago
13

Snowy's Snow Cones has a special bubble gum snow cone on sale. The cone is a regular snow cone that has a spherical piece of bub

ble gum nested at the bottom of the cone. The radius of the snow cone is 2 inches, and the height of the cone is 3 inches. If the diameter of the bubble gum is 0.5 inches, which of the following can be used to calculate the volume of the cone that can be filled with flavored ice? (5 points)
1 over 3 (3.14)(22)(3) − 4 over 3 (3.14)(0.53)
1 over 3 (3.14)(32)(2) − 4 over 3 (3.14)(0.53)
1 over 3 (3.14)(32)(2) − 4 over 3 (3.14)(0.253)
1 over 3 (3.14)(22)(3) − 4 over 3 (3.14)(0.253)
Mathematics
1 answer:
Dmitrij [34]2 years ago
3 0

Answer:

1 over 3 (3.14)(32)(2) − 4 over 3 (3.14)(0.53)

Step-by-step explanation:

not sure but i think this is the right answer

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Arlecino [84]
Domain = x<18000(You cant og a negative number)
Am I actually supposed to graph it? enter the equation on desmos.com
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t=50log(18000/(18000-4000))=50log(18000/14000)=5.457
5 0
3 years ago
How do you solve l v
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5 0
3 years ago
I need help with number 2 please.
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3 years ago
Anny goes bowling. He has $25.00 to spend. He spends $4.25 to rent shoes. He spends $2.50 for each game he bowls. Which inequali
spayn [35]

Answer:

D. 25 +4.25x < 25

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Fast-food restaurants spend quite a bit of time studying the amount of time cars spend in their drive-throughs. Certainly, the f
melisa1 [442]

Answer:

For the 99th percentile, we have X = 206 seconds.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 138.5, \sigma = 29

99th percentile:

Value of X when Z has a pvalue of 0.99. So we use Z = 2.325

Z = \frac{X - \mu}{\sigma}

2.325 = \frac{X - 138.5}{29}

X - 138.5 = 29*2.325

X = 205.92 = 206

For the 99th percentile, we have X = 206 seconds.

4 0
3 years ago
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