How would you do 5^-1 (mod 26) ?

Mathematics

1 answer:

Yuri [45]3 years ago

3 0

What we’re looking for is the value of k that will satisfy the equation.

The solution would be like this for this specific problem:

5k =1 (mod 26)

Check how 5*5 = 25 = -1 (mod 26)

In this way, 5*(-5) = -5*5 = -25 = -(-1) = 1 (mod 26)

Thus, k = -5 = 21 (mod 26)

And 5^-1 = 21 (mod 26)

I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

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