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3 years ago

How would you do 5^-1 (mod 26) ?

Mathematics

1 answer:

Yuri [45]3 years ago

3 0

What we’re looking for is the value of k that will satisfy the equation.

The solution would be like this for this specific problem:

5k =1 (mod 26)

Check how 5*5 = 25 = -1 (mod 26)

In this way, 5*(-5) = -5*5 = -25 = -(-1) = 1 (mod 26)

Thus, k = -5 = 21 (mod 26)

And 5^-1 = 21 (mod 26)

I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

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2 years ago

Simplify this algebraic expression. z- 4/4+8 A. Z-7 B. Z+9 C. 2-3 D. Z+7

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Answer:

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Step-by-step explanation:

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2 years ago

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Challenge: What is the area of the base of a figure if the volume is 210 ft^3 and the height is 14 ft?

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3 years ago

What is the quadratic. Formula?

balu736 [363]

Answer:

$x = \frac{ - b ± \sqrt{ {b }^{2} - 4ac } }{2a}$

Step-by-step explanation:

For example, we'll use this quadratic equation.

${x}^{2} + 5x + 6$

To understand how to plug it into the formula we need to know what each term represents.

$a {x}^{2} + bx + c$

So the equation above would be put into the formula like this.

$x = \frac{ - 5± \sqrt{ {5}^{2} - 4(1)(6) } }{2(1)}$

Then we would solve

$\frac{ - 5± \sqrt{25 - 24} }{2} \\ \\ = \frac{ -5±1}{2}$

Now, the equation will branch off into one that solves when addition and one when subtraction.

$\frac{ - 5 + 1}{2} = \frac{ - 4}{2} = - 2 \\ \\ \frac{ - 5 - 1}{2} = \frac{ - 6}{2} = - 3$

So x={-3, -2} (-3 and -2)

6 0

3 years ago

The school that Joe goes to is selling tickets to a choral performance. On血e first day of ticket

ArbitrLikvidat [17]

Answer:

The price of one senior citizen ticket is $8, and the price of one child ticket is $11.

Step-by-step explanation:

You are looking for two things: the price of a senior citizen ticket and the price of a child ticket.

We need to write two equations using two variables.

Let s = price of 1 senior citizen ticket.

Let c = price of 1 child ticket.

First day of ticket sales:

6 senior citizen tickets, 8 child tickets, total sales of $136

Since s is the price of a senior citizen ticket, 6 tickets cost 6s.

Since c is the price of a child ticket, 8 tickets cost 8c.

The total sales is 6s + 8c.

The total sales is $136, so our first equation is

6s + 8c = 136

Now we do the same for the second day of ticket sales.

6 senior citizen tickets, 9 child tickets, total sales of $147.

Since s is the price of a senior citizen ticket, 6 tickets cost 6s.

Since c is the price of a child ticket, 9 tickets cost 9c.

The total sales is 6s + 9c.

The total sales is $147, so our second equation is

6s + 9c = 147

The system of equations is

6s + 8c = 136

6s + 9c = 147

Multiply both sides of the first equation by -1. Write the second equation below it. Then add the equations.

-6s - 8c = -136

(+) 6s + 9c = 147

----------------------------

c = 11

c = 11, so the cost of a child ticket is $11.

Now substitute 11 for c in the first equation, and solve for s.

6s + 8c = 136

6s + 8(11) = 136

6s + 88 = 136

6s = 48

s = 8

The price of a senior citizen ticket is $8.

The price of a senior citizen ticket is $8, and the price of a child ticket is $11.

6 0

3 years ago