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3 years ago

How would you do 5^-1 (mod 26) ?

Mathematics

1 answer:

Yuri [45]3 years ago

3 0

What we’re looking for is the value of k that will satisfy the equation.

The solution would be like this for this specific problem:

5k =1 (mod 26)

Check how 5*5 = 25 = -1 (mod 26)

In this way, 5*(-5) = -5*5 = -25 = -(-1) = 1 (mod 26)

Thus, k = -5 = 21 (mod 26)

And 5^-1 = 21 (mod 26)

I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

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Which line segment is not a diameter or radius of circle F?

spin [16.1K]

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Argument
Take F to be the center. The line segment that IS a diameter or radius must either go through F (that would make the line a diameter) or to be a radius the segment mus end in F and touch the circumference once. See below.

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3 years ago

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Answer:

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Step-by-step explanation:

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Read 2 more answers

2 + 2 ez badge yeah ok now what do i do

Marrrta [24]

Answer:

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3 years ago

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Flura [38]

Answer:

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Step-by-step explanation:

From the table it is clear that the line is passing through the points $(0,\: -2)= (x_1, \:y_1) \: \&\: (-6, \:0)=(x_2,\:y_2)$

(There are many other points in the table and any two of them can chosen as per our convenience)

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4 years ago

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Dahasolnce [82]

Answer:

-1/2

Step-by-step explanation:

y2-y1 4-5 -1

--------- = -------- = --------

x2-x1 6-4 2

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