2 years ago

What is the slope of the line that passes through the points (2, 3) and (8, 6)

Mathematics

1 answer:

Rainbow [258]2 years ago

7 0

Using rise over run and y2 - y1 over x2 - x1, the slope is 3/6, which reduces to 1/2.

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Been stuck on this for a while man....................

bonufazy [111]

Answer:

2) 6

4) 9

Step-by-step explanation:

7 0

3 years ago

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What is the solution to the system of equations <br><br> 3x+2y=39<br> 5x-y=13

Vadim26 [7]

Hiya. I'm going to rewrite the second equation.

By subtracting 5x by both sides, I'll be able to have y by itself:

-y=-5x+13

I'm going to then divide both sides by -1 to get:

y=5x-13.

Then, I'm going to plug that equation into the first equation

3x+2(5x-13)=39

Factor:

3x+10x-26=39

Combine like terms:

13x=65

Divide both sides by 13 to get x by itself to get x=5

Plug this back into the equation of y=5x-13

y=5(5)-13 to get y=12

4 0

3 years ago

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HELP PLEASE ASAP!!!!! QUICK ;--;

Reika [66]

The answer to your question is 9,9

4 0

3 years ago

Samantha drew Triangle JKL with the coordinates (2,3), (4, 3) and (5,2). She reflected this image over the x-axis to create an i

zavuch27 [327]

Answer:

J'(2,-3), K'(4, -3) and L'(5,-2)

Step-by-step explanation:

The given triangle has vertices at J(2,3), K(4, 3) and L(5,2).

The transformation rule for a reflection in the x-axis is:

$(x,y)\to (x,-y)$

We substitute the points to obtain the coordinates of the image triangle J'K'L'

$J(2,3)\to J'(2,-3)$

$K(4,3)\to K'(4,-3)$

$L(5,2)\to L'(5,-2)$

In other words, we negate the y-coordinates of triangle JKL to obtain the coordinates of J'K'L'

See attachment for graph.

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3 years ago

I had fell asleep but this for the nikkas det wanted to see what i look like <3

exis [7]

Answer:

yes

Step-by-step explanation:

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3 years ago