Answer:
1Na₂S + 1Cd(C₂H₃O₂)₂ → 1CdS + 2NaC₂H₃O
Explanation:
1Na₂S + 1Cd(C₂H₃O₂)₂ → 1CdS + 1NaC₂H₃O₂
1Na₂S + 1Cd(C₂H₃O₂)₂ → 1CdS + 2NaC₂H₃O₂
(on the reactant side there are two molecules of C₂H₃O₂ and 2 atoms of Na, so in order to balance that we put the coefficient 2 on NAC₂H₃O₂)
So the final product is
3.33 atm
P1/T1 = P2/T2
5 atm/ 300 K = P2 /200K
P2 = 5atm*200 K/300 K
P2 = 3.33 atm
1.51834×10^22
Number of atom=Mass/Molar Mass × avogadros constant
2.3g/91.224g/mol × 6.203×10^23
