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Aleks04 [339]
3 years ago
8

Describe how the size of sediment particles affects their movement during deflation.

Chemistry
2 answers:
Solnce55 [7]3 years ago
8 0

Answer:

Deflation refers to the process in which the wind blowing over the ground picks up small particles of sediments along with it. It has been seen that the size of the sediment particles influences their movement at the time of deflation.

When the wind blowing has more energy, it can move larger particles of the sediments along with it. Usually, the small, and fine particles can be picked up and blown along the air. The particles of medium size skip and bounce along the ground, and the large size particles roll and slide along the ground.

lutik1710 [3]3 years ago
7 0
The larger the piece the longer it will take to break down. This is because it has more mass that needs to be broken down. Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
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12.00 moles of naclo3 will produce how many grams of O2? (Moles to Grams)
Sergeu [11.5K]
2NaClO₃   →  2NaCl  +  3O₂

mole ratio of NaClO₃  to  O₂  is  2  :  3

∴  if moles of NaClO₃  =  12 mol

then moles of O₂  =  \frac{12 mol   *   3}{2}
      
                             =  18 mol


Mass of O₂  =  mol of O₂  ×  molar mass of O₂
 
                    =  18 mol  × 16 g/mol
 
                    =  288 g

So I wasn't sure which equation to use since you did not specify so I just used the decomposition reaction.  If you should have used another reaction then just follow the same steps and you'll get your answer.




4 0
2 years ago
Which of the following is true for the theoretical yield of a reaction? (1 point)
just olya [345]

Answer:

It is always twice the value of the actual yield.

Explanation:

3 0
2 years ago
Why do you think the placebo effect works
timurjin [86]

Answer:

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7 0
2 years ago
a drop of gasoline has a mass of 22 mg and a density of 0.754 g/cm^3. What is its volume in cubic centimeters?
Verizon [17]
The density can be calculated using the following rule:
density = mass/volume
therefore,
volume = mass/density

we have the mass=22 mg=0.022 grams and density=0.754g/cm^3

substituting in the above equation, we can calculate the volume as follows:
volume = 0.022/0.754 = 0.0291 cm^3
7 0
2 years ago
6. Determine the wavelength for a photon of light
MAVERICK [17]

Answer:

6) λ  =  0.84 × 10⁻⁸ m

7) λ  =  0.84 × 10⁻⁶ m

Explanation:

6) Given data:

Wavelength of photon = ?

Frequency of photon = 3.56 × 10¹⁶ Hz

Solution:

Formula:

Speed of radiation = frequency × wavelength

c = speed of wave = 3×10⁸ m/s

by putting values,

3×10⁸ m/s  = 3.56 × 10¹⁶ Hz ×  λ

λ  =  3×10⁸ m/s   / 3.56 × 10¹⁶ s⁻¹

λ  =  0.84 × 10⁻⁸ m

7) Given data:

Wavelength of photon = ?

Frequency of photon = 6.15 × 10¹⁴ Hz

Solution:

Formula:

Speed of radiation = frequency × wavelength

c = speed of wave = 3×10⁸ m/s

by putting values,

3×10⁸ m/s  =  6.15 × 10¹⁴ Hz ×  λ

λ  =  3×10⁸ m/s   /  6.15 × 10¹⁴ Hz s⁻¹

λ  =  0.84 × 10⁻⁶ m

6 0
2 years ago
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