Question

Under what pressure will a scientist need to store 0.400 moles of gas if the container has a volume of 200.0 mL and the temperature is kept at 23.0 C?

Answer 1

Answer: 48.60 atm

Explanation: Using ideal gas equation:

$PV=nRT$

$P=\frac{nRT}{V}$

P= pressure = ? atm

V= volume =$200ml=0.2L$  

n = no of moles = 0.400

R= gas constant =0.0821 Latm/molK

T = Temperature $=23^0C=(23+273)K=296K$

$P=\frac{0.400\times 0.0821\times 296K}{0.2L}=48.60atm$

Answer 2

P*V=n*R*T where p is the pressure, v the volume in L, n the quantity in moles, R a standard number that should be given and T the temperature in Kelvin
R=8.32 (usually)
T(in K)=273+T(in Celsius) so T=296K
P*V=n*R*T
P=n*R*T/V
P=0.4*8.32*296/0.2