Based on the enthalpy of the reaction, 41625 kJ of heat is needed to produce 1850 grams of ammonia (NH3).
<h3>What is heat of reaction?</h3>
The heat of reaction or enthalpy change is the heat absorbed or evolved when reactant molecules react to form products.
According the enthalpy value of the reaction, 4 moles of ammonia require 1530 kJ of heat for its formation.
Molar mass of ammonia = 17 g
Mass of 4 moles of ammonia = 4 × 17 = 68 g
1850 g of ammonia will require = 1850 × 1530/68 = 41625 kJ of heat.
Therefore, 41625 kJ of heat is needed to produce 1850 grams of ammonia (NH3).
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Answer:
6 moles
Explanation:
From the equation you can see that twice as many HCL moles are used as H2 produced
2 x 3 = 6 moles of HCL required
Cars might not be as insulated and as safe because of the need to get cooler air into the vehicle, and im not fully sure but refrigerators would still run on ice to cool food. Houses wouldnt be as insulated from heat so when winter came around you would be colder than normal <span />
We have Kc = 4.2 x 10^-2 (given but missing in the question)
and When the balanced equation for this reaction is:
PCl5(g) ↔ PCl3(g) + Cl2(g)
so, according to the Kc formula:
Kc = the concentration of products / the concentration of the reactants
so, to get the concentration of the reactants in equilibrium, the concentration of the products / the concentration of the reactants should equal the Kc value which is given in the question (missing in your question).
So by substitution in Kc formula:
Kc = [PCl3]*[Cl2] / [PCl5]
4.2 x 10^-2 = 0.18 * 0.25 /[PCl5]
∴[PCl5] = 0.18*0.25 / 4.2x10^-2 = 1.07
So the concentration of the reactants in equilibrim = 1.07
In order to calculate the number of atoms, we must first know the number of moles present. And
moles = (mass present) / (molecular mass)
Therefore, the moles of Mg present are
170 / 24 = 7.08
The number of atoms in a mole of substance is given by Avagadro's Number which is 6.02 x 10^23
Since there are 7.08 moles, there are:
7.08 * 6.02*10^23
= 4.26 * 10^24 atoms
