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alukav5142 [94]
3 years ago
8

Which of the following can lower the activation energy of a system?

Chemistry
1 answer:
aleksandrvk [35]3 years ago
8 0

wrong boiiiiiiiiiiii

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In the following equation:
Luda [366]

Answer:

FeCl₃

Explanation:

                 4FeCl₃  +   3O₂     => 2Fe₂O₃+ 6Cl₂

Given =>  7moles     9moles

A simple way to determine which reagent is the limiting reactant is to convert all given data to moles then divide by the respective coefficients of the balanced equation. The smaller value will be the limiting reactant.

                 4FeCl₃     +   3O₂     => 2Fe₂O₃+ 6Cl₂

Given =>  7/4 = 1.75*     9/3 = 3

*Smaller value => FeCl₃ is limiting reactant.  

NOTE: However, when working problems, one must use original mole values given.

   

7 0
3 years ago
What's your favorite song ​
Inessa [10]
Run it up by nav and lemonade by dont oliver
3 0
3 years ago
Please help me I will really appreciate it !!!! And Please no links
BigorU [14]

Explanation:

Steaming up or fogging happens when steam condenses on the mirror. Steam emerging from hot water can condense on a colder surface. That’s the reason you can see the result on a mirror instantaneously. Obviously, for a bathroom mirror to steam up, the steam that originates at the shower spray (or the bathtub) has to travel through the cooler air to reach the mirror. Since air tends to heat up easily, the mirror can steam up fast.

3 0
2 years ago
What assumptions do we make in order to use the Henderson-Hasselbalch equation? a. Both the weak acid and its conjugate base are
zepelin [54]

Answer:

The final and initial concentration of the acid and it's conjugate base are approximately equal, that is we use the weak acid approximation.

Explanation:

The Henderson-Hasselbalch is used to calculate the pH of a buffer solution. It depends on the weak acid approximation.

Since the weak acid ionizes only to a small extent, then we can say that [HA] ≈ [HA]i

Where [HA] = final concentration of the acid and [HA]i = initial concentration of the acid.

It also follows that [A^-] ≈ [A^-]i where [A^-] and[A^-]i refer to final and initial concentrations of the conjugate base hence the answer above.

7 0
2 years ago
I don't need to know why i just want the awnser
Lubov Fominskaja [6]

Answer:

I remember doing this in 7th,

1. D

2. B or D, more leaning on B though

3. A

4 0
3 years ago
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