Answer:
in the simple cubic unit cell, the centers of ____Eight________ identical particles define the ____corners________ of a cube. The particles do touch along the cube's _____edges _______ but do not touch along the cube's ___ diagonally_________ or through the center. There is/are __eight__________ particle per unit cell and the coordination number is _____six_______ .
Your question is incomplete. However, I found a similar problem fromanother website as shown in the attached picture.
To solve this problem, you must know that at STP, the volume for any gas is 22.4 L/mol. So,
Moles O₂: 156.8 mL * 1 L/1000 mL* 1 mol/22.4 L = 0.007 moles
Mass calcium: 0.007 mol O₂ * 2 mol Ca/1 mol O₂ * 40 g/mol Ca =
<em> 0.56 g Ca</em>
Answer:
YOU BETTER GIVE THEM BRAINLEIST ↑↑↑↑↑
Explanation:
The number of C atoms in 0.524 moles of C is 3.15 atoms.
The number of 
molecules in 9.87 moles is 59.43 molecules.
The moles of Fe in 1.40 x 
atoms of Fe is 0.23 x 
The moles of 
in 2.30x
molecules of is 3.81.
<h3>What are moles?</h3>
A mole is defined as 6.02214076 × 
of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
A. The number of C atoms in 0.524 mole of C:
6.02214076 × x 0.524 mole
3.155601758 atoms =3.155 atoms
B. The number of molecules in 9.87 moles of :
6.02214076 × x 9.87
59.4385293 molecules= 59.43 molecules
C. The moles of Fe in 1.40 x atoms of Fe:
1.40 x ÷ 6.02214076 ×
0.2324754694 x moles.
0.23 x moles.
D. The moles of in 2.30x molecules of :
2.30x ÷ 6.02214076 ×
3.819239854 moles=3.81 moles
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The volume of ethyne, C₂H₂ required to produce 12 moles of CO₂ assuming the reaction is at STP is 134.4 L
<h3>Balanced equation</h3>
2C₂H₂(g) + 5O₂(g) --> 4CO₂(g) + 2H₂O(g)
From the balanced equation above,
4 moles of CO₂ were produced by 2 moles of C₂H₂
<h3>How to determine the mole of C₂H₂ needed to produce 12 moles of CO₂</h3>
From the balanced equation above,
4 moles of CO₂ were produced by 2 moles of C₂H₂
Therefore,
12 moles of CO₂ will be produce by = (12 × 2) / 4 = 6 moles of C₂H₂
<h3>How to determine the volume (in L) of C₂H₂ needed at STP</h3>
At standard temperature and pressure (STP),
1 mole of C₂H₂ = 22.4 L
Therefore,
6 moles of C₂H₂ = 6 × 22.4
6 moles of C₂H₂ = 134.4 L
Thus, we can conclude that the volume of C₂H₂ needed for the reaction at STP is 134.4 L
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