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gregori [183]
3 years ago
9

What is AB? a. 6cm b. 9cm c. 4cm d. 2.2cm

Mathematics
1 answer:
Fed [463]3 years ago
7 0

Answer:

AB = 4 cm

Step-by-step explanation:

The tangent and secant are drawn from an external point to the circle.

Then the square of the measure of the tangent is equal to the product of the external part of the secant and the entire secant.

let AB = x, then

x(x + 5) = 6²

x² + 5x = 36 ( subtract 36 from both sides )

x² + 5x - 36 = 0 ← in standard form

(x + 9)(x - 4) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 9 = 0 ⇒ x = - 9

x - 4 = 0 ⇒ x = 4

However x > 0 ⇒ x = 4 ⇒ b = 4 CM

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3 0
3 years ago
A car is travelling at exactly 6 miles per hour and accelerates at a constant rate to exactly 65 miles per hour.
vichka [17]

Answer:

14878.04878miles/hours^2

Step-by-step explanation:

Let's find a solution by understanding the following:

The acceleration rate is defined as the change of velocity within a time interval, which can be written as:

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Using the problem's data we have:

Vf=65miles/hour

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Using the acceleration rate equation we have:

A=(65miles/hour - 6miles/hour)/14.8seconds, but look that velocities use 'hours' unit while 'T' uses 'seconds'.

So we need to transform 14.8seconds into Xhours, as follows:

X=(14.8seconds)*(1hours/60minutes)*(1minute/60seconds)

X=0.0041hours

Using X=0.0041hours in the previous equation instead of 14.8seconds we  have:

A=(65miles/hour - 6miles/hour)/0.0041hours

A=(61miles/hour)/0.0041hours

A=(61miles)/(hour*0.0041hours)

A=61miles/0.0041hours^2

A=14878.04878miles/hours^2

In conclusion, the acceleration rate is 14878.04878miles/hours^2

7 0
3 years ago
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(3, - 2)

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subtract 4 from both sides

- 2x = - 6 ( divide both sides by - 2 )

x = \frac{-6}{-2} = 3


3 0
3 years ago
Read 2 more answers
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