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3 years ago

What is AB? a. 6cm b. 9cm c. 4cm d. 2.2cm

Mathematics

1 answer:

Fed [463]3 years ago

7 0

Answer:

AB = 4 cm

Step-by-step explanation:

The tangent and secant are drawn from an external point to the circle.

Then the square of the measure of the tangent is equal to the product of the external part of the secant and the entire secant.

let AB = x, then

x(x + 5) = 6²

x² + 5x = 36 ( subtract 36 from both sides )

x² + 5x - 36 = 0 ← in standard form

(x + 9)(x - 4) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 9 = 0 ⇒ x = - 9

x - 4 = 0 ⇒ x = 4

However x > 0 ⇒ x = 4 ⇒ b = 4 CM

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Alik [6]

Answer:

$x =15$

Step-by-step explanation:

In $\odot D,$ AB and AC are chords which are equidistant from the center of the circle.

$\therefore Chord \: AB \cong Chord\: AC$

$\therefore m \widehat {AB} = m\widehat {AC}$

(Equal chords intercept equal arcs)

$\because m \widehat {AB} = (10x-23)\degree$

$\therefore m \widehat {AC} = (10x-23)\degree$

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$(10x-23)\degree + (10x-23)\degree= 360\degree- 106\degree$

$2(10x-23)\degree = 254\degree$

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2 years ago

7. A patient has a urinary tract infection so Dr. Padron prescribes Ancef. A 1200 mL bag contains 400 mg of Ancef. If the patien

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3 years ago

Simplify 3p^4(4p^4 7p^3 4p 1

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I hope this helps you

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3 years ago

(3.8 x 10 ^ -6) x (2.37 x 10 ^ -3)<br><br> Enter the answer in science notification

Black_prince [1.1K]

Multiply the coefficients and the powers of 10 with each other:

$(3.8 \times 10^{-6}) \times (2.37 \times 10^{-3}) = (3.8\times2.37) \times (10^{-6} \times10^{-3})$

The numeric part simply yields

$3.8\times2.37 = 9.006$

As for the powers of 10, you have to add the exponents, using the rule

$a^b \times a^c = a^{b+c}$

So, we have

$10^{-6} \times10^{-3} = 10^{-6-3} = 10^{-9}$

So, the final answer is

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3 years ago