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rodikova [14]
3 years ago
11

Along hot spots, vast amounts of basaltic lava can flow from fissures, forming:

Physics
1 answer:
Fynjy0 [20]3 years ago
8 0

The answer would be flood basalt. This is the outcome of a huge volcanic eruption or sequence of eruptions that covers large expanses of land or the ocean floor with basalt lava. The development and effects of a flood basalt hinge on a variety of factors, like latitude, continental configuration, rate, volume, period of eruption, the preexisting climate state, style and location, and the biota flexibility to alteration.

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You are spinning a rock, of mass 0.75 kg, at the end of a string of length 0.86m in a vertical circle in uniform circular motion
Nina [5.8K]

Answer:

v (minimum speed) = 2.90 m/sec.

\\ \\ maximum speed (v)= 6.57 m/sec.\\

Maximum value of speed will occur at lowest point of vertical circle.

Explanation:

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Using the force balance expression at the top of the circle,

Gravitational Force + Tension force = Centrifugal force

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v = \sqrt{g*R}

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v (minimum speed) = 2.90 m/sec.

b) what is the maximum speed the rock can have so that the string does not break?

Here the  force balance at bottom of circle is represented by the illustration:

T = m*g + m*v^2/R

Given that:

maximum tension T = 45 N

maximum speed v = ??

mass  m = 0.75 kg

∴

45 - 0.75*9.81 = 0.75*\frac{v^2}{0.86} \\\\v^2 = 0.86*(45 - 0.75*9.81)/0.75 \\ v = \sqrt{0.86*(45 - 0.75*9.81)/0.75\\ maximum speed (v)= 6.57 m/sec.\\

c)

At what point in the vertical circle does this maximum value occur?

Maximum value of speed will occur at lowest point of vertical circle.

This is so because  at the lowest point; the tension in string will be maximum.

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A car is traveling with a constant speed when the driver suddenly applies the brakes, causing the car to slow down with a consta
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An ideal monatomic gas at 275 K expands adiabatically and reversibly to six times its volume. What is its final temperature (in
Gwar [14]

The final temperature is 83 K.

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{T}_{1} = 275 \; K  

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\therefore \cfrac{T}{275} = {\left( \cfrac{V}{6V} \right)}^{\frac{5}{3} - 1}

 

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