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2 years ago

14

Please help me to find out my mistake

1 answer:

Scrat [10]2 years ago

7 0

From the calculation, the speed of sound at 10 K is 63.5 m/s.

<h3>What is the speed of sound?</h3>

We know that the speed of sound is directly proportional to the temperature of the body thus we can write;

V1/V2 = √T1/T2

Then;

T1 = 0 degrees or 273 K

T2 = 10 K

V1 = 330 m/s

V2 = ?

330/T2 = √273/10

330/T2 = 5.2

330 = 5.2T2

V2 = 330/5.2

V2 = 63.5 m/s

Learn more about speed of sound:brainly.com/question/15381147

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A(n) ____________________ valve operates similarly to a direct-acting sequence valve except that it has an external pilot line t

katrin [286]

Answer:

A remote controlled (<em>or externally piloted) </em>sequence valve

Explanation:

First of all, a sequence valve is a pressure-operated valve that opens at an adjustable set pressure.

Sequence valves can be internally piloted or externally piloted.

Internally piloted sequence valves are known as direct-acting sequence valve. This means that the pressure change they sense is from their main inlet valve.
Externally piloted sequence valves have a pilot line in which the pilot signal to open the valve is from a source other than the line feeding it.

External pilot-operated sequence valves can be used to open and allow flow when a remote operation reaches a certain predetermined pressure.

4 0

3 years ago

If a ball is thrown vertically upward from the roof of 32 foot building with a velocity of 64 ft/sec, its height after t seconds

stepan [7]

Answer:

a) $s_{max} = 96\,ft$ , b) $v(4.449\,s) = -78.368\,\frac{ft}{s}$

Explanation:

a) The maximum height is obtained with the help of the First and Second Derivative Tests:

First Derivative

$v(t) = 64 - 32\cdot t$

$64 - 32\cdot t = 0$

$t = 2\,s$

Second Derivative

$a(t) = -32$ (absolute maximum)

The maximum height reached by the ball is:

$s (2\,s) = 32 + 64\cdot (2\,s) - 16\cdot (2\,s)^{2}$

$s_{max} = 96\,ft$

b) The time required by the ball to hit the ground is:

$32+64\cdot t - 16\cdot t^{2} = 0$

$-16\cdot (t^{2}-4\cdot t - 2) = 0$

$t^{2}-4\cdot t - 2 = 0$

$(t -4.449)\cdot (t+0.449)\approx 0$

Just one root offers a solution that is physically reasonable:

$t = 4.449\,s$

The velocity of the ball when it hits the ground is:

$v(4.449\,s) = 64 - 32\cdot (4.449\,s)$

$v(4.449\,s) = -78.368\,\frac{ft}{s}$

6 0

3 years ago

Read 2 more answers

A 98.0 N grocery cart is pushed 12.0 m along an aisle by a shopper who exerts a constant horizontal force of 40.0 N. If all fric

Digiron [165]

Answer:

9.8 m/s

Explanation:

The work done by the force pushing the cart is equal to the kinetic energy gained by the cart:

$W=K_f -K_i$

where

W is the work done

$K_f$ is the final kinetic energy of the cart

$K_i$ is the initial kinetic energy of the cart, which is zero because the cart starts from rest, so we can write:

$W=K_f$

But the work is equal to the product between the pushing force F and the displacement, so

$W=Fd=(40.0 N)(12.0 m)=480 J$

So, the final kinetic energy of the cart is 480 J. The formula for the kinetic energy is

$K_f=\frac{1}{2}mv^2$ (1)

where m is the mass of the cart and v its final speed.

We can find the mass because we know the weight of the cart, 98.0 N:

$m=\frac{F_g}{g}=\frac{98.0 N}{9.8 m/s^2}=10 kg$

Therefore, we can now re-arrange eq.(1) to find the final speed of the cart:

$v=\sqrt{\frac{2K_f}{m}}=\sqrt{\frac{2(480 J)}{10 kg}}=9.8 m/s$

7 0

3 years ago

The only way to slow down a moving object is to apply a net force to it.

salantis [7]

Hey there,

Answer:

A, True

Hope this helps :D

<em>~Top☺
</em>

4 0

3 years ago

Where could convection currents form? Check all that apply.

Sladkaya [172]

In a fresh water lake
atmosphere
earths mantle

8 0

4 years ago

Read 2 more answers