At a local hospital, 35 babies were born. if 26 were boys, what percentage of the newborns were boys?

1 answer:

3 0

Remember to divide the numerator by the denominator and multiply it by 100.

So 26 divided by 35 is 0.7428..... Since the number doesn't end, you round it to the nearest tenth, which is 0.7. Now you multiply that number by 100. And the percentage would be... 70% of the babies would be boys.

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zavuch27 [327]

Answer:

The bottom for an A is 75. Round to the nearest whole number as needed.

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Let X the random variable that represent the scores on this case, and for this case we know the distribution for X is given by:

$X \sim N(\mu=73,\sigma=7)$

And let $\bar X$ represent the sample mean, the distribution for the sample mean is given by:

$\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})$

2) The bottom for an A is _____. Round to the nearest whole number as needed.

And we want the top 5.5% of the scores, so we need a value a such that:

$P(X>a)=0.055$ or $P(X$

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$z=\frac{x-\mu}{\sigma}$

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"=NORM.INV(0.945,0,1)"

If we apply the z score formula to our case we have this:

$P(X$