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To make a search term more accurate, you must keep it simple and you must be able to use more specific terms. The more specific you are with what you are asking the engine about, the more friendlier it will respond.
The answer is Option B. I hope this answer helped you!
Even numbers are numbers whigh are divisible by 2. Therefore, the first even number is 2. A pseudocode which adds the first 100 even numbers can be written thus :
counter = 0
sum = 0
interval = 2
while counter < 100 :
sum = sum + interval
interval += 2
counter +=1
print(sum)
- A counter takes count of the number of values summed
- Initializes a variable which holds the sum of even values
- Since even numbers are divisible by 2; every factor ; increase every added value by 2
- The program ends once counter is 100
Learn more : brainly.com/question/25327166
The Correct choice is " True "
When the animation and the graphic designs are used to sell products or services, it is known as multimedia advertising.
Answer:
Following is the code for filter:
public class filter
{ public static void main(String[] args)
{ int x = StdIn.readInt();
System.out.print(" " + x + " ");
while(!StdIn.isEmpty())
{ int y = StdIn.readInt();
if(y != x)
System.out.print(" " + y + " ");
x = y;
}
}
}
Explanation:
- A public class filter is used.
- The main function will accept a single argument as string[], it is also known as java command line argument.
- Now the Stdln.readInt is used to read the integers in the sequence and store it in integer x.
- The value stored in variable x will be printed using System.out.print
- Now unless the Stdln.readInt gets an empty value, check each value of sequence and store in variable y.
- If y is not equal to previous value x, print it and shift the value of y into x.
- Repeat the loop again.
i hope it will help you!
Answer:
it is complex
employees are not involved
