Based on the observations made and experiments performed over the last
Answer:
4.465 m
Explanation:
Taken the beam to be uniform, then the center of gravity will act at the mid-point of the beam. The mid point = 11 / 2 = 5.5 m
since the boy can walk to the end of the beam without falling,
then the torque ( moment of the force) by beam = torque by students at the end of the beam
let the distance of the boy = x
220 ( 5.5 - x ) = 51 × x
1210 - 220 x = 51 x
1210 = 51 x + 220 x
1210 = 271 x
x = 1210 / 271 = 4.465 m
Answer:
y(m=+1,-1)=3.36mm
Explanation:
We have to take into account the expression for the position of the fringes
Where lambda is the wavelength of the light, D is the distance to the screen, m is the order of the fringe and d is the distance between slits.
By replacing we have
There is a distance of 3.36mm to the secon maximum in the screen.
HOPE THIS HELPS!!
Answer:
Minimum angular spread (in rad) = 547.45 x 10⁻⁶ rad
Explanation:
GIven;
Wavelength of manganese vapor laser beam = 534 nm = 534 x 10⁻⁹ m
Diameter = 1.19 mm = 1.19 x 10⁻³ m
Find:
Minimum angular spread (in rad)
Computation:
Minimum angular spread (in rad) = 1.22[Wavelength / Diameter]
Minimum angular spread (in rad) = 1.222[(534 x 10⁻⁹) / (1.19 x 10⁻³)]
Minimum angular spread (in rad) = 2[448.73 x 10⁻⁶]
Minimum angular spread (in rad) = 547.45 x 10⁻⁶ rad