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Nata [24]
3 years ago
13

Bob is pushing a box across the floor at a constant speed of 1.5 m/s, applying a horizontal force whose magnitude is 60 n. alice

is pushing an identical box across the floor at a constant speed of 3 m/s, applying a horizontal force. (a) what is the magnitude of the force that alice is applying to the box?
Physics
1 answer:
earnstyle [38]3 years ago
7 0

120n

since the speed is doubled, her force is doubled

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A reaction in which x and y form products was found to be first order in x and zero order in y. by what factor will the rate of
Studentka2010 [4]
In zero order reactions the rate of reaction is independent of reactant concentrations. That is the rate of the reaction does not vary with increasing nor decreasing reactants concentrations. On the other hand, first order reaction are reactions in which the rate of reaction is directly proportional to the concentration of the reacting substance (reactants). In this case, i believe the rate of reaction will triple( increase by a factor of 3)
7 0
3 years ago
A piece of silicon sample has a resistivity of 0.1 ω.Cm. Its thickness is 100µm. The electron mobility is 1350cm 2 v -1sec-1. Wh
lawyer [7]

The answer is Rh = 135 cm^3 and B = 0.05185 wh/m^2


Explanation:

Resitivity of silicon = 0.1

thickness = 100um

so, I = ma

Required to find out concentration of electron , we know that

Rh = up

By putting in the values,

Rh = 1350 x 0.1

Rh = 135 cm^3


Now consider,

Rh = 1 / Rh.q

= 1 / Rh . q

= 1 / 135 x1.609 x10^-19

= 4.6037 x 10^16 / cm^3

Vh = BIRh / w

B = Vh w/ IRh

B = -70 x10^-6 x 100 x10^-6 / 1x 10^-3 x 135 x 10^-6

B = 0.05185 wh / m^2


5 0
3 years ago
Why is MA always less than VR?​
jarptica [38.1K]

Answer:

\boxed{ \bold{ \boxed{ \sf{see \: below}}}}

Explanation:

MA ( Mechanical Advantage ) is always less than VR ( Velocity Ratio ) because <u>MA</u><u> </u><u>is</u><u> </u><u>reduced</u><u> </u><u>by</u><u> </u><u>friction</u><u> </u><u>but</u><u> </u><u>VR</u><u> </u><u>is</u><u> </u><u>not</u><u> </u><u>affected</u><u> </u><u>by</u><u> </u><u>friction</u><u>.</u>

Hope I helped!

Best regards! :D

6 0
3 years ago
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