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bixtya [17]
3 years ago
5

When a researcher wants to correlate tension with depression, she develops tests that measure these two emotional states. The te

sts are her _________ of the variables she is interested in.
Physics
2 answers:
Igoryamba3 years ago
8 0

Answer:

The answer is: measuring instrument

Explanation:

The researcher develops test to measure the variables she is interested in. So, they are her measuring instrument.

german3 years ago
3 0

Answer:

<h2>Operational definitions.</h2>

Explanation:

Operational definitions is a detailed, concise, precise and clear definition of a measure. It's applied when collecting data for a research, and it's a mandatory process, because this way the research will have precise defintion about the variables, which also determines the specific situation the researcher is going to study.

So, using operational definition of the variables, there won't be room for imprecise perspective in the research, and the investigator is gonna know specifically what is he or she studying.

Therefore, operational definitions completes the blank here.

<em />

<em>When a researcher wants to correlate tension with depression, she develops tests that measure these two emotional states. The tests are her </em><em>operational definitions</em><em> of the variables she is interested in.</em>

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Calculate the force of gravity on the 1.2-kg mass if it were 1.9×107 m above earth's surface (that is, if it were four earth rad
Anettt [7]

Answer:

Force of gravity, F = 0.74 N

Mass of an object, m = 1.2 kg

Distance above earth's surface, d=1.9\times 10^7\ m

Mass of Earth, M=5.97\times 10^{24}\ kg

Radius of Earth, r=6.37\times 10^6\ m

We need to find the force of gravity above the surface of Earth. It is given by :

F=G\dfrac{mM}{R^2}

R = r + d

R = 25370000 m

F=6.67\times 10^{-11}\times \dfrac{5.97\times 10^{24}\ kg\times 1.2\ kg}{(25370000\ m)^2}

F = 0.74 N

So, the force of gravity on the object is 0.74 N. Hence, this is the required solution.

5 0
4 years ago
What other places in the world use hydro kinetic energy to generate electrical power?
Elina [12.6K]

Answer:

Alaska: Hydrokinetic Energy Campbell CR9000X used for in-stream hydrokinetic device evaluation. Marine hydrokinetic energy power generation is an emerging sector in the renewable energy portfolio. Hydrokinetic devices convert the energy of waves, tidal currents, ocean currents or river currents into electrical power.

3 0
4 years ago
C) Explain the following.<br>Keftles, cooking pans and iron boxes have polished surfaces​
Monica [59]

Answer:

Polished surfaces reduce heat loss

5 0
3 years ago
A car has a mass of 1,000 kilograms. The weight of the car is
ahrayia [7]

Answer : The weight of the car is 9800 N

Explanation :

It is given that,

The mass of the car, m = 1000 kg

We have to find the weight of the car. The weight of an object is defined as the force acting on it under the action of gravity. The mass of an object is the amount of matter present in it.

Using second law of motion :

W = m g

Where

m is the mass of the car

g is the acceleration due to gravity g = 9.8 N/kg

W = 1000 kg × 9.8 N/kg

W = 9800 N

So, the weight of the car is 9800 N.

Hence, this is the required solution.

6 0
4 years ago
In this problem you will consider the balance of thermal energy radiated and absorbed by a person.Assume that the person is wear
Viefleur [7K]

Answer:P=14.6 W

Explanation:

According to the Stefan-Boltzmann law for real radiating bodies:

P=\sigma A \epsilon T^{4} (1)

Where:

P is the energy radiated (in Watts)

\sigma=5.67(10)^{-8}\frac{W}{m^{2} K^{4}} is the Stefan-Boltzmann's constant.  

A is the Surface area of the body  

T=30\°C + 273.15= 303.15 K is the effective temperature of the body (its surface absolute temperature) in Kelvin

\epsilon=0.6 is the body's emissivity

On the other hand, we are told the human body is roughly approximated to a cylinder of length L=2.0m and circumference C=0.8m.

The circumference of a circle is:C=0.8m=2 \pi r where r is the radius. Hence r=\frac{0.8m}{2 \pi}=0.1273 m.

Now we have to input this value for r  in the Area of a cylinder formula:

A=\pi r^{2}L

A=\pi (0.1273 m)^{2}(2 m)

A=0.0509 m^{2} (2)

Substituting (2) in (1):

P=(5.67(10)^{-8}\frac{W}{m^{2} K^{4}}) (0.0509 m^{2}) (0.6) (303.15 K)^{4} (3)

Finally:

P=14.62 W \approx 14.6 W

5 0
3 years ago
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