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algol [13]
1 year ago
14

A drone is flying horizontally when it runs out of battery and begins to free fall from 20m. No drag. If it lands 60m away (in t

he x-direction) from where it began to fall, what was it's horizontal velocity while it fell
Physics
1 answer:
rewona [7]1 year ago
3 0

Answer:

Explanation:

Remark

At the time it takes to drop 20 m is the same time it takes to travel 60 m horizontally.

Givens

h = 20 m

hd = 60 m

g = 9.81

vi = 0

Formula

d = vi*t + 1/2 a * t^2                  We are solving for t

Solution

When the battery fails, the vertical initial velocity is 0. So we have to find the time it would take to drop 20 meters

d = 0*t + 1/2 * 9.81 a* t^2

20 = 4.91 * t^2                          Divide by 4.91

20/4.91 = 4.91 t^2 / 4.91    

4.073 = t^2                              Take the square root of both sides.

t = 2.02 seconds

Horizontal

d = 60 m

t = 2.02 seconds

v = ?

Note: there is no horizontal deceleration or acceleration

v = d/t

v = 60/2.02

Answer: v = 29.73 m/s

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Let p is the total momentum of the system before the collision. It is given by :

p=mu+m'u'\\\\p=0.25\times 0.31+0.5\times (-0.22)\\\\p=-0.0325\ kg-m/s

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Describe the earth's rotation on it axis
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