You have to know a great deal more about where Q and Q' are before you can say much of anything. The problem is listed a s a middle school problem so you are likely permitted to go by the way it looks, but that is not a habit that I would continue using.
So if the triangles SQR and S'Q'R' are congruent, and if they are orientated exactly the same way which means that the distance between QQ' and RR' is a constant (and those are big ifs), then you can claim that QQ' is parallel to the other two lines. Is it the same length as the other two? Again, you obtained the other two by measurement. It looks like SQR and S'Q'R' are equilateral and if that is correct then yes they lengths are all equal. But your marker could do just about anything with this question.
If you have a person marking this, talk it over with them. I say QQ' is equal and parallel to the other two, but don't be surprised if it is wrong.
Answer:
<h2>
34</h2>
Step-by-step explanation:
Sum interior of triangles add up to 180 degrees. So add 103 + 43 to get 146 then subtract 180 - 146 to get 34 as the last missing angle of the triangle
Answer:
<u><em>7 (3/4)</em></u>
Step-by-step explanation:
how many times does 4 go into 11?....
2 times which would be 8 then
then you add up the remaining numbers to the fraction which it would be
3/4
put it together it would be
2 (3/4)
finally you add the 5 and the 2 which your finally answer would be
7 (3/4)
<em>hope it helps:)</em>
Answer:
Zoe's number is 6
Step-by-step explanation:
Let the number be 'n'
a) Multiply 'n' by 3 ⇒ n*3 = 3n
Add 4 to '3n' ⇒ 3n + 4
Add 5 to 'n' ⇒ n +5
Multiply (n+ 5) by 2 ⇒ (n +5)*2 = 2n + 5*2 = 2n + 10
3n + 4 = 2n + 10
b) 3n + 4 = 2n + 10
Subtract 4 form both sides
3n = 2n + 10 - 4
3n = 2n + 6
Subtract 2n from both sides
3n - 2n = 6
