Let x = length of the park
Let y = width of the park
Because the area is 392392 ft², therefore
xy = 392392 (1)
Because three sides of fencing measure 5656 ft, therefore
2x + y = 5656 (2)
That is
y = 5656 - 2x (3)
Substitute (3) into (1).
x(5656 - 2x) = 392392
5656x - 2x² = 392392
2x² -5656x + 392392 = 0
x² - 2828x + 196196 = 0
Solve with the quadratic formula.
x = (1/2)*[2828 +/- √(2828² - 4*196196)]
= 2756.83 or 71.17
Answer:
The possible dimensions are 2756.8 ft and 71.2 ft (nearest tenth)
Answer:
Translation, rotation and reflection
Step-by-step explanation:
Congruent images remain the same.
Translation, rotation and reflection preserve congruence while dilation will not.
Step-by-step explanation:
15X - 4Y when X=7 Y=8
=15*(7) - 4*(8)
= 105 - 32
=73
I believe the answer you are looking for is the quadratic formula. because it has the formula correct, and it to me just looks exactly like it.
So, it has the ax^2+bx+c=0 but just a little difference, it has a subtracting sign instead of adding.
I don't know if I am right, but that is my guess. I remember doing those lol
Ac method
for
ax^2+bx+c
multiply a and c together
find what 2 numbers multiply to get ac and add to get b
split b up
gropu
factor
3x^2+7x+2
2 times 3=6
what 2 numbers multily to get 6 and ad to get 7
6 and 1
3x^2+6x+1x+2
(3x^2+6x)+(1x+2)
3x(x+2)+1(x+2)
(3x+1)(x+2) is factored
